Preverite, ali je dani niz mogoče razdeliti na štiri različne nize
Preizkusite na GfG Practice 
Izhod
Naloga niza je preveriti, ali ga lahko razdelimo na 4 nize, tako da je vsak niz neprazen in drugačen od drugega.
Primeri:
Vnos : str[] = 'geeksforgeeks'
Izhod : Da
'geeks' 'for' 'gee' 'ks' so štirje različni nizi, ki se lahko oblikujejo iz danega niza.
Vnos : str[] = 'aaabb'
Izhod : Ne
Opazujte, če je dolžina niza večja ali enaka 10, potem se lahko vsak čas razdeli na štiri dele. Recimo, da je dolžina 10, potem je mogoče sestaviti niz dolžine 1 2 3 4.
Za niz, ki ima dolžino manj kot 10, lahko uporabimo surovo silo, tj. ponovimo vse možne načine razdelitve niza in preverimo vsakega.
če dolžina je več kot 10
vrni resnico
drugače (Če je dolžina manjša od 10)
Uporabite metodo Brute Force, da preverite, ali ga lahko razdelimo na štiri različne nize.
Spodaj je izvedba zgornje ideje.
C++ // C++ program to check if we can break a string // into four distinct strings. #include using namespace std ; // Return if the given string can be split or not. bool check ( string s ) { // We can always break a string of size 10 or // more into four distinct strings. if ( s . size () >= 10 ) return true ; // Brute Force for ( int i = 1 ; i < s . size (); i ++ ) { for ( int j = i + 1 ; j < s . size (); j ++ ) { for ( int k = j + 1 ; k < s . size (); k ++ ) { // Making 4 string from the given string string s1 = s . substr ( 0 i ); string s2 = s . substr ( i j - i ); string s3 = s . substr ( j k - j ); string s4 = s . substr ( k s . size () - k ); // Checking if they are distinct or not. if ( s1 != s2 && s1 != s3 && s1 != s4 && s2 != s3 && s2 != s4 && s3 != s4 ) return true ; } } } return false ; } // Driven Program int main () { string str = 'aaabb' ; ( check ( str )) ? ( cout < < 'Yes' < < endl ) : ( cout < < 'No' < < endl ); return 0 ; }
Java // Java program to check if we can break a string // into four distinct strings. class GFG { // Return true if both strings are equal public static boolean strcheck ( String s1 String s2 ) { if ( s1 != s2 ) return false ; return true ; } // Return if the given string can be split or not. public static boolean check ( String s ) { if ( s . length () >= 10 ) return true ; // Brute Force for ( int i = 1 ; i < s . length (); i ++ ) { for ( int j = i + 1 ; j < s . length (); j ++ ) { for ( int k = j + 1 ; k < s . length (); k ++ ) { // Making 4 string from the given string String s1 = '' s2 = '' s3 = '' s4 = '' ; try { s1 = s . substring ( 0 i ); s2 = s . substring ( i j - i ); s3 = s . substring ( j k - j ); s4 = s . substring ( k s . length () - k ); } catch ( StringIndexOutOfBoundsException e ) { } // Checking if they are distinct or not. if ( strcheck ( s1 s2 ) && strcheck ( s1 s3 ) && strcheck ( s1 s4 ) && strcheck ( s2 s3 ) && strcheck ( s2 s4 ) && strcheck ( s3 s4 )) return true ; } } } return false ; } // Driver code public static void main ( String [] args ) { String str = 'aaabb' ; if ( check ( str )) System . out . println ( 'Yes' ); else System . out . println ( 'No' ); } } // This code is contributed by // sanjeev2552
Python # Python3 program to check if we can # break a into four distinct strings. # Return if the given string can be # split or not. def check ( s ): # We can always break a of size 10 or # more into four distinct strings. if ( len ( s ) >= 10 ): return True # Brute Force for i in range ( 1 len ( s )): for j in range ( i + 1 len ( s )): for k in range ( j + 1 len ( s )): # Making 4 from the given s1 = s [ 0 : i ] s2 = s [ i : j - i ] s3 = s [ j : k - j ] s4 = s [ k : len ( s ) - k ] # Checking if they are distinct or not. if ( s1 != s2 and s1 != s3 and s1 != s4 and s2 != s3 and s2 != s4 and s3 != s4 ): return True return False # Driver Code if __name__ == '__main__' : str = 'aaabb' print ( 'Yes' ) if ( check ( str )) else print ( 'NO' ) # This code is contributed # by SHUBHAMSINGH10
C# // C# program to check if we can break a string // into four distinct strings. using System ; class GFG { // Return true if both strings are equal public static Boolean strcheck ( String s1 String s2 ) { if ( s1 . CompareTo ( s2 ) != 0 ) return false ; return true ; } // Return if the given string // can be split or not. public static Boolean check ( String s ) { if ( s . Length >= 10 ) return true ; // Brute Force for ( int i = 1 ; i < s . Length ; i ++ ) { for ( int j = i + 1 ; j < s . Length ; j ++ ) { for ( int k = j + 1 ; k < s . Length ; k ++ ) { // Making 4 string from the given string String s1 = '' s2 = '' s3 = '' s4 = '' ; try { s1 = s . Substring ( 0 i ); s2 = s . Substring ( i j - i ); s3 = s . Substring ( j k - j ); s4 = s . Substring ( k s . Length - k ); } catch ( Exception e ) { } // Checking if they are distinct or not. if ( strcheck ( s1 s2 ) && strcheck ( s1 s3 ) && strcheck ( s1 s4 ) && strcheck ( s2 s3 ) && strcheck ( s2 s4 ) && strcheck ( s3 s4 )) return true ; } } } return false ; } // Driver code public static void Main ( String [] args ) { String str = 'aaabb' ; if ( check ( str )) Console . WriteLine ( 'Yes' ); else Console . WriteLine ( 'No' ); } } // This code is contributed by Princi Singh
JavaScript < script > // JavaScript program to check if we can break a string // into four distinct strings. // Return true if both strings are equal function strcheck ( s1 s2 ) { if ( s1 . localeCompare ( s2 ) != 0 ) return false ; return true ; } // Return if the given string can be split or not. function check ( s ) { if ( s . length >= 10 ) return true ; // Brute Force for ( let i = 1 ; i < s . length ; i ++ ) { for ( let j = i + 1 ; j < s . length ; j ++ ) { for ( let k = j + 1 ; k < s . length ; k ++ ) { // Making 4 string from the given string let s1 = '' s2 = '' s3 = '' s4 = '' ; s1 = s . substring ( 0 i ); s2 = s . substring ( i i + j - i ); s3 = s . substring ( j j + k - j ); s4 = s . substring ( k k + s . length - k ); // Checking if they are distinct or not. if ( strcheck ( s1 s2 ) && strcheck ( s1 s3 ) && strcheck ( s1 s4 ) && strcheck ( s2 s3 ) && strcheck ( s2 s4 ) && strcheck ( s3 s4 )) return true ; } } } return false ; } let str = 'aaabb' ; if ( check ( str )) document . write ( 'Yes' ); else document . write ( 'No' ); < /script>
PHP // Return true if the given string can be split into four distinct strings function check ( $s ) { // We can always break a string of size 10 or more into four distinct strings if ( strlen ( $s ) >= 10 ) { return true ; } // Brute Force for ( $i = 1 ; $i < strlen ( $s ); $i ++ ) { for ( $j = $i + 1 ; $j < strlen ( $s ); $j ++ ) { for ( $k = $j + 1 ; $k < strlen ( $s ); $k ++ ) { // Making 4 from the given string $s1 = substr ( $s 0 $i ); $s2 = substr ( $s $i $j - $i ); $s3 = substr ( $s $j $k - $j ); $s4 = substr ( $s $k strlen ( $s ) - $k ); // Checking if they are distinct or not if ( $s1 != $s2 && $s1 != $s3 && $s1 != $s4 && $s2 != $s3 && $s2 != $s4 && $s3 != $s4 ) { return true ; } } } } return false ; } // Driver Code $str = 'aaabb' ; echo ( check ( $str ) ? 'Yes' : 'NO' ); ?>
Izhod
No
Časovna zapletenost : O(n 3 )
Pomožni prostor: O(n)
Ustvari kviz
