Maximalt element mellan två noder av BST
Med tanke på en mängd n element och två heltal a b som tillhör den givna arrayen. Skapa en Binärt sökträd genom att infoga element från arr[0] till arr[n-1] . Uppgiften är att hitta maximal element i vägen från a till b.
Exempel:
Ingång: arr[] = { 18 36 9 6 12 10 1 8 } a = 1 b = 10.
Utgång: 12
Förklaring: Väg från 1 till 10 innehåller { 1 6 9 12 10 } . Det maximala elementet är 12.
Innehållsförteckning
- [Naiv metod] Använda hashing - O(n * log n) Tid och O(n) Mellanrum
- [Förväntat tillvägagångssätt] Använder LCA för två noder - O(h) Tid och O(h) Space
[Naiv metod] Använda hashing - O(n * log n) Tid och O(n) Mellanrum
Tanken är att använda en hashmap att lagra förälder nod för varje nod i binärt sökträd . Vi kan utgå från båda de givna noderna och gå upp i trädet och lagra noderna som påträffas i en uppsättning . När vi når roten eller en gemensam förfader till de två noderna kan vi korsa ner trädet från varje nod och hitta maximal element som påträffas i uppsättningen av noder.
Algoritmsteg för ovanstående tillvägagångssätt:
- Skapa en tom hashtabell att lagra förälder nod för varje nod i det binära sökträdet.
- Utför a djup-först sökning (DFS) genomgång av det binära sökträdet och fyll i hashtabellen med föräldranoden för varje nod.
- Initiera två pekare säger pl och p2 till de givna noderna.
- Initiera två tomma uppsättningar säg s1 och s2 för att lagra noderna som påträffas när du korsar trädet från pl och p2 respektive.
- Medan pl och p2 är inte lika gör följande:
- Om p1 inte är det null lägg till den i set s1 och uppdatera p1 till sin överordnade nod med hjälp av hashtabellen.
- Om p2 inte är det null lägg till den i set s2 och uppdatera p2 till sin överordnade nod med hjälp av hashtabellen.
- Hitta skärningsuppsättningen av s1 och s2 dvs uppsättningen av noder som är gemensamma för både s1 och s2.
- I denna korsning hitta maximal element och returnera det.
Nedan är implementeringen av ovanstående tillvägagångssätt:
C++ // C++ program to find maximum element in the path // between two Nodes of Binary Search Tree. #include using namespace std ; class Node { public : int data ; Node * left * right ; Node ( int x ) { data = x ; left = right = nullptr ; } }; // Insert a new Node in Binary Search Tree void insertNode ( Node *& root int x ) { Node * current = root * parent = nullptr ; // Traverse to the correct position for insertion while ( current != nullptr ) { parent = current ; if ( x < current -> data ) current = current -> left ; else current = current -> right ; } // Insert new Node at the correct position if ( parent == nullptr ) root = new Node ( x ); else if ( x < parent -> data ) parent -> left = new Node ( x ); else parent -> right = new Node ( x ); } // DFS to populate parent map for each node void dfs ( Node * root unordered_map < Node * Node *> & parentMap Node * parent = nullptr ) { if ( ! root ) return ; // Store the parent of the current node if ( parent != nullptr ) { parentMap [ root ] = parent ; } // Recur for left and right children dfs ( root -> left parentMap root ); dfs ( root -> right parentMap root ); } // Function to find the node with the given value in the BST Node * findNode ( Node * root int val ) { if ( ! root ) return nullptr ; if ( root -> data == val ) return root ; Node * leftResult = findNode ( root -> left val ); if ( leftResult ) return leftResult ; return findNode ( root -> right val ); } // Find maximum element in the path between two nodes in BST int findMaxElement ( Node * root int x int y ) { unordered_map < Node * Node *> parentMap ; // Populate parent map with DFS dfs ( root parentMap ); // Find the nodes corresponding to the // values x and y Node * p1 = findNode ( root x ); Node * p2 = findNode ( root y ); // If nodes not found if ( ! p1 || ! p2 ) return -1 ; // Sets to store nodes encountered // while traversing up the tree unordered_set < Node *> s1 s2 ; // Variable to store the maximum // element in the path int maxElement = INT_MIN ; // Traverse up the tree from p1 and p2 // and add nodes to sets s1 and s2 while ( p1 != p2 ) { if ( p1 ) { s1 . insert ( p1 ); maxElement = max ( maxElement p1 -> data ); // Move to parent node p1 = parentMap [ p1 ]; } if ( p2 ) { s2 . insert ( p2 ); maxElement = max ( maxElement p2 -> data ); p2 = parentMap [ p2 ]; } // Check if there's a common node // in both sets if ( s1 . count ( p2 )) break ; if ( s2 . count ( p1 )) break ; } // Now both p1 and p2 point to their Lowest // Common Ancestor (LCA) maxElement = max ( maxElement p1 -> data ); return maxElement ; } int main () { vector < int > arr = { 18 36 9 6 12 10 1 8 }; int a = 1 b = 10 ; int n = arr . size (); Node * root = new Node ( arr [ 0 ]); for ( int i = 1 ; i < n ; i ++ ) insertNode ( root arr [ i ]); cout < < findMaxElement ( root a b ) < < endl ; return 0 ; }
Java // Java program to find the maximum element in the path // between two Nodes of Binary Search Tree. import java.util.* ; class Node { int data ; Node left right ; Node ( int x ) { data = x ; left = right = null ; } } class GfG { // Insert a new Node in Binary Search Tree static void insertNode ( Node root int x ) { Node current = root parent = null ; // Traverse to the correct position // for insertion while ( current != null ) { parent = current ; if ( x < current . data ) current = current . left ; else current = current . right ; } // Insert new Node at the correct position if ( parent == null ) root = new Node ( x ); else if ( x < parent . data ) parent . left = new Node ( x ); else parent . right = new Node ( x ); } // DFS to populate parent map for each node static void dfs ( Node root Map < Node Node > parentMap Node parent ) { if ( root == null ) return ; // Store the parent of the current node if ( parent != null ) { parentMap . put ( root parent ); } // Recur for left and right children dfs ( root . left parentMap root ); dfs ( root . right parentMap root ); } // Function to find the node with the given // value in the BST static Node findNode ( Node root int val ) { if ( root == null ) return null ; if ( root . data == val ) return root ; Node leftResult = findNode ( root . left val ); if ( leftResult != null ) return leftResult ; return findNode ( root . right val ); } // Find maximum element in the path between // two nodes in BST static int findMaxElement ( Node root int x int y ) { Map < Node Node > parentMap = new HashMap <> (); // Populate parent map with DFS dfs ( root parentMap null ); // Find the nodes corresponding to // the values x and y Node p1 = findNode ( root x ); Node p2 = findNode ( root y ); // If nodes not found if ( p1 == null || p2 == null ) return - 1 ; // Sets to store nodes encountered // while traversing up the tree Set < Node > s1 = new HashSet <> (); Set < Node > s2 = new HashSet <> (); // Variable to store the maximum element // in the path int maxElement = Integer . MIN_VALUE ; // Traverse up the tree from p1 and p2 // and add nodes to sets s1 and s2 while ( p1 != p2 ) { if ( p1 != null ) { s1 . add ( p1 ); maxElement = Math . max ( maxElement p1 . data ); // Move to parent node p1 = parentMap . get ( p1 ); } if ( p2 != null ) { s2 . add ( p2 ); maxElement = Math . max ( maxElement p2 . data ); p2 = parentMap . get ( p2 ); } // Check if there's a common node in both sets if ( s1 . contains ( p2 )) break ; if ( s2 . contains ( p1 )) break ; } // Now both p1 and p2 point to their // Lowest Common Ancestor (LCA) maxElement = Math . max ( maxElement p1 . data ); return maxElement ; } public static void main ( String [] args ) { int [] arr = { 18 36 9 6 12 10 1 8 }; int a = 1 b = 10 ; int n = arr . length ; Node root = new Node ( arr [ 0 ] ); for ( int i = 1 ; i < n ; i ++ ) insertNode ( root arr [ i ] ); System . out . println ( findMaxElement ( root a b )); } }
Python # Python program to find maximum element in the path # between two Nodes of Binary Search Tree. class Node : def __init__ ( self x ): self . data = x self . left = None self . right = None # Insert a new Node in Binary Search Tree def insert_node ( root x ): current = root parent = None # Traverse to the correct position for insertion while current is not None : parent = current if x < current . data : current = current . left else : current = current . right # Insert new Node at the correct position if parent is None : root = Node ( x ) elif x < parent . data : parent . left = Node ( x ) else : parent . right = Node ( x ) # DFS to populate parent map for each node def dfs ( root parent_map parent = None ): if root is None : return # Store the parent of the current node if parent is not None : parent_map [ root ] = parent # Recur for left and right children dfs ( root . left parent_map root ) dfs ( root . right parent_map root ) # Function to find the node with the given # value in the BST def find_node ( root val ): if root is None : return None if root . data == val : return root left_result = find_node ( root . left val ) if left_result : return left_result return find_node ( root . right val ) # Find maximum element in the path between # two nodes in BST def find_max_element ( root x y ): parent_map = {} # Populate parent map with DFS dfs ( root parent_map ) # Find the nodes corresponding to the # values x and y p1 = find_node ( root x ) p2 = find_node ( root y ) # If nodes not found if not p1 or not p2 : return - 1 # Sets to store nodes encountered # while traversing up the tree s1 = set () s2 = set () # Variable to store the maximum element in the path max_element = float ( '-inf' ) # Traverse up the tree from p1 and p2 # and add nodes to sets s1 and s2 while p1 != p2 : if p1 : s1 . add ( p1 ) max_element = max ( max_element p1 . data ) # Move to parent node p1 = parent_map . get ( p1 ) if p2 : s2 . add ( p2 ) max_element = max ( max_element p2 . data ) p2 = parent_map . get ( p2 ) # Check if there's a common node in both sets if p2 in s1 : break if p1 in s2 : break # Now both p1 and p2 point to their # Lowest Common Ancestor (LCA) max_element = max ( max_element p1 . data ) return max_element if __name__ == '__main__' : arr = [ 18 36 9 6 12 10 1 8 ] a b = 1 10 n = len ( arr ) root = Node ( arr [ 0 ]) for i in range ( 1 n ): insert_node ( root arr [ i ]) print ( find_max_element ( root a b ))
C# // C# program to find the maximum element in the path // between two Nodes of Binary Search Tree. using System ; using System.Collections.Generic ; class Node { public int data ; public Node left right ; public Node ( int x ) { data = x ; left = right = null ; } } class GfG { // Insert a new Node in Binary Search Tree static public void insertNode ( Node root int x ) { Node current = root parent = null ; // Traverse to the correct position // for insertion while ( current != null ) { parent = current ; if ( x < current . data ) current = current . left ; else current = current . right ; } // Insert new Node at the correct // position if ( parent == null ) root = new Node ( x ); else if ( x < parent . data ) parent . left = new Node ( x ); else parent . right = new Node ( x ); } // DFS to populate parent map for each node static public void dfs ( Node root Dictionary < Node Node > parentMap Node parent ) { if ( root == null ) return ; // Store the parent of the current node if ( parent != null ) { parentMap [ root ] = parent ; } // Recur for left and right children dfs ( root . left parentMap root ); dfs ( root . right parentMap root ); } // Function to find the node with the given // value in the BST static public Node findNode ( Node root int val ) { if ( root == null ) return null ; if ( root . data == val ) return root ; Node leftResult = findNode ( root . left val ); if ( leftResult != null ) return leftResult ; return findNode ( root . right val ); } // Find maximum element in the path between // two nodes in BST static public int findMaxElement ( Node root int x int y ) { Dictionary < Node Node > parentMap = new Dictionary < Node Node > (); // Populate parent map with DFS dfs ( root parentMap null ); // Find the nodes corresponding to // the values x and y Node p1 = findNode ( root x ); Node p2 = findNode ( root y ); // If nodes not found if ( p1 == null || p2 == null ) return - 1 ; // Sets to store nodes encountered // while traversing up the tree HashSet < Node > s1 = new HashSet < Node > (); HashSet < Node > s2 = new HashSet < Node > (); // Variable to store the maximum element // in the path int maxElement = int . MinValue ; // Traverse up the tree from p1 and p2 // and add nodes to sets s1 and s2 while ( p1 != p2 ) { if ( p1 != null ) { s1 . Add ( p1 ); maxElement = Math . Max ( maxElement p1 . data ); // Move to parent node p1 = parentMap [ p1 ]; } if ( p2 != null ) { s2 . Add ( p2 ); maxElement = Math . Max ( maxElement p2 . data ); p2 = parentMap [ p2 ]; } // Check if there's a common node in both sets if ( s1 . Contains ( p2 )) break ; if ( s2 . Contains ( p1 )) break ; } // Now both p1 and p2 point to their Lowest // Common Ancestor (LCA) maxElement = Math . Max ( maxElement p1 . data ); return maxElement ; } static void Main () { int [] arr = { 18 36 9 6 12 10 1 8 }; int a = 1 b = 10 ; int n = arr . Length ; Node root = new Node ( arr [ 0 ]); for ( int i = 1 ; i < n ; i ++ ) insertNode ( root arr [ i ]); Console . WriteLine ( findMaxElement ( root a b )); } }
JavaScript // JavaScript program to find the maximum element in the path // between two Nodes of Binary Search Tree. class Node { constructor ( x ) { this . data = x ; this . left = this . right = null ; } } // Insert a new Node in Binary Search Tree function insertNode ( root x ) { let current = root parent = null ; // Traverse to the correct position for insertion while ( current !== null ) { parent = current ; if ( x < current . data ) current = current . left ; else current = current . right ; } // Insert new Node at the correct position if ( parent === null ) root = new Node ( x ); else if ( x < parent . data ) parent . left = new Node ( x ); else parent . right = new Node ( x ); } // DFS to populate parent map for each node function dfs ( root parentMap parent = null ) { if ( root === null ) return ; // Store the parent of the current node if ( parent !== null ) { parentMap . set ( root parent ); } // Recur for left and right children dfs ( root . left parentMap root ); dfs ( root . right parentMap root ); } // Function to find the node with the given // value in the BST function findNode ( root val ) { if ( root === null ) return null ; if ( root . data === val ) return root ; let leftResult = findNode ( root . left val ); if ( leftResult !== null ) return leftResult ; return findNode ( root . right val ); } // Find maximum element in the path // between two nodes in BST function findMaxElement ( root x y ) { let parentMap = new Map (); // Populate parent map with DFS dfs ( root parentMap ); // Find the nodes corresponding to the // values x and y let p1 = findNode ( root x ); let p2 = findNode ( root y ); // If nodes not found if ( p1 === null || p2 === null ) return - 1 ; // Sets to store nodes encountered let s1 = new Set (); let s2 = new Set (); // Variable to store the maximum // element in the path let maxElement = - Infinity ; // Traverse up the tree from p1 and p2 // and add nodes to sets s1 and s2 while ( p1 !== p2 ) { if ( p1 !== null ) { s1 . add ( p1 ); maxElement = Math . max ( maxElement p1 . data ); // Move to parent node p1 = parentMap . get ( p1 ); } if ( p2 !== null ) { s2 . add ( p2 ); maxElement = Math . max ( maxElement p2 . data ); p2 = parentMap . get ( p2 ); } // Check if there's a common node in both sets if ( s1 . has ( p2 )) break ; if ( s2 . has ( p1 )) break ; } // Now both p1 and p2 point to their Lowest // Common Ancestor (LCA) maxElement = Math . max ( maxElement p1 . data ); return maxElement ; } let arr = [ 18 36 9 6 12 10 1 8 ]; let a = 1 b = 10 ; let n = arr . length ; let root = new Node ( arr [ 0 ]); for ( let i = 1 ; i < n ; i ++ ) insertNode ( root arr [ i ]); console . log ( findMaxElement ( root a b ));
Produktion
12
[Förväntat tillvägagångssätt] Använder LCA för två noder - O(h) Tid och O(h) Space
Tanken är att hitta Lägsta gemensamma anfader av nod 'a' och nod 'b'. Sök sedan maximal nod mellan LCA och 'a' och hitta även den maximala noden mellan LCA och 'b'. Svaret kommer att vara maximal nod på två.
Nedan är implementeringen av ovanstående algoritm:
C++ // C++ program to find maximum element in the path // between two Nodes of Binary Search Tree. #include using namespace std ; class Node { public : Node * left * right ; int data ; Node ( int x ) { data = x ; left = right = nullptr ; } }; // Insert a new Node in Binary Search Tree. void insertNode ( struct Node * root int x ) { Node * current = root * parent = nullptr ; while ( current != nullptr ) { parent = current ; if ( current -> data < x ) current = current -> right ; else current = current -> left ; } if ( parent == nullptr ) current = new Node ( x ); else { if ( parent -> data < x ) parent -> right = new Node ( x ); else parent -> left = new Node ( x ); } } // Return the maximum element between a Node // and its given ancestor. int maxelpath ( Node * root int x ) { Node * current = root ; int mx = INT_MIN ; // Traversing the path between ancestor and // Node and finding maximum element. while ( current -> data != x ) { if ( current -> data > x ) { mx = max ( mx current -> data ); current = current -> left ; } else { mx = max ( mx current -> data ); current = current -> right ; } } return max ( mx x ); } // Return maximum element in the path between // two given Node of BST. int maximumElement ( Node * root int x int y ) { Node * current = root ; // Finding the LCA of Node x and Node y while (( x < current -> data && y < current -> data ) || ( x > current -> data && y > current -> data )) { // Checking if both the Node lie on the // left side of the parent p. if ( x < current -> data && y < current -> data ) current = current -> left ; // Checking if both the Node lie on the // right side of the parent p. else if ( x > current -> data && y > current -> data ) current = current -> right ; } // Return the maximum of maximum elements occur // in path from ancestor to both Node. return max ( maxelpath ( current x ) maxelpath ( current y )); } int main () { int arr [] = { 18 36 9 6 12 10 1 8 }; int a = 1 b = 10 ; int n = sizeof ( arr ) / sizeof ( arr [ 0 ]); Node * root = new Node ( arr [ 0 ]); for ( int i = 1 ; i < n ; i ++ ) insertNode ( root arr [ i ]); cout < < maximumElement ( root a b ) < < endl ; return 0 ; }
Java // Java program to find maximum element in the path // between two Nodes of Binary Search Tree. import java.util.* ; class Node { int data ; Node left right ; Node ( int x ) { data = x ; left = right = null ; } } class GfG { // Insert a new Node in Binary Search Tree static void insertNode ( Node root int x ) { Node current = root parent = null ; // Traverse to the correct // position for insertion while ( current != null ) { parent = current ; if ( x < current . data ) current = current . left ; else current = current . right ; } // Insert new Node at the correct // position if ( parent == null ) root = new Node ( x ); else if ( x < parent . data ) parent . left = new Node ( x ); else parent . right = new Node ( x ); } // Find maximum element in the path from // an ancestor to a node static int maxInPath ( Node root int x ) { int maxElement = Integer . MIN_VALUE ; Node current = root ; // Traverse the path from root to the // target node 'x' while ( current != null && current . data != x ) { maxElement = Math . max ( maxElement current . data ); if ( x < current . data ) current = current . left ; else current = current . right ; } return Math . max ( maxElement x ); } // Find maximum element in the path between two // nodes in BST static int findMaxElement ( Node root int x int y ) { Node current = root ; // Find Lowest Common Ancestor (LCA) of x and y while (( x < current . data && y < current . data ) || ( x > current . data && y > current . data )) { if ( x < current . data && y < current . data ) current = current . left ; else if ( x > current . data && y > current . data ) current = current . right ; } // Find maximum elements in paths from LCA // to x and LCA to y return Math . max ( maxInPath ( current x ) maxInPath ( current y )); } public static void main ( String [] args ) { int [] arr = { 18 36 9 6 12 10 1 8 }; int a = 1 b = 10 ; Node root = new Node ( arr [ 0 ] ); for ( int i = 1 ; i < arr . length ; i ++ ) insertNode ( root arr [ i ] ); System . out . println ( findMaxElement ( root a b )); } }
Python # Python program to find maximum element in the path # between two Nodes of Binary Search Tree. class Node : def __init__ ( self x ): self . data = x self . left = None self . right = None # Insert a new Node in Binary Search Tree def insertNode ( root x ): current = root parent = None # Traverse to the correct position for insertion while current is not None : parent = current if x < current . data : current = current . left else : current = current . right # Insert new Node at the correct position if parent is None : root = Node ( x ) elif x < parent . data : parent . left = Node ( x ) else : parent . right = Node ( x ) # Find maximum element in the path from an # ancestor to a node def maxInPath ( root x ): maxElement = float ( '-inf' ) current = root # Traverse the path from root to the # target node 'x' while current is not None and current . data != x : maxElement = max ( maxElement current . data ) if x < current . data : current = current . left else : current = current . right return max ( maxElement x ) # Find maximum element in the path between # two nodes in BST def findMaxElement ( root x y ): current = root # Find Lowest Common Ancestor (LCA) of x and y while ( x < current . data and y < current . data ) or ( x > current . data and y > current . data ): if x < current . data and y < current . data : current = current . left elif x > current . data and y > current . data : current = current . right # Find maximum elements in paths from LCA to # x and LCA to y return max ( maxInPath ( current x ) maxInPath ( current y )) if __name__ == '__main__' : arr = [ 18 36 9 6 12 10 1 8 ] a b = 1 10 root = Node ( arr [ 0 ]) for i in range ( 1 len ( arr )): insertNode ( root arr [ i ]) print ( findMaxElement ( root a b ))
C# // C# program to find maximum element in the path // between two Nodes of Binary Search Tree. using System ; class Node { public int data ; public Node left right ; public Node ( int x ) { data = x ; left = right = null ; } } class GfG { // Insert a new Node in Binary Search Tree static void insertNode ( Node root int x ) { Node current = root parent = null ; // Traverse to the correct position // for insertion while ( current != null ) { parent = current ; if ( x < current . data ) current = current . left ; else current = current . right ; } // Insert new Node at the correct position if ( parent == null ) root = new Node ( x ); else if ( x < parent . data ) parent . left = new Node ( x ); else parent . right = new Node ( x ); } // Find maximum element in the path from an // ancestor to a node static int maxInPath ( Node root int x ) { int maxElement = int . MinValue ; Node current = root ; // Traverse the path from root to the target node 'x' while ( current != null && current . data != x ) { maxElement = Math . Max ( maxElement current . data ); if ( x < current . data ) current = current . left ; else current = current . right ; } return Math . Max ( maxElement x ); } // Find maximum element in the path between two nodes in BST static int findMaxElement ( Node root int x int y ) { Node current = root ; // Find Lowest Common Ancestor (LCA) of x and y while (( x < current . data && y < current . data ) || ( x > current . data && y > current . data )) { if ( x < current . data && y < current . data ) current = current . left ; else if ( x > current . data && y > current . data ) current = current . right ; } // Find maximum elements in paths from // LCA to x and LCA to y return Math . Max ( maxInPath ( current x ) maxInPath ( current y )); } static void Main () { int [] arr = { 18 36 9 6 12 10 1 8 }; int a = 1 b = 10 ; Node root = new Node ( arr [ 0 ]); for ( int i = 1 ; i < arr . Length ; i ++ ) insertNode ( root arr [ i ]); Console . WriteLine ( findMaxElement ( root a b )); } }
JavaScript // JavaScript program to find maximum element in the path // between two Nodes of Binary Search Tree. class Node { constructor ( x ) { this . data = x ; this . left = null ; this . right = null ; } } // Insert a new Node in Binary Search Tree function insertNode ( root x ) { let current = root parent = null ; // Traverse to the correct position for insertion while ( current !== null ) { parent = current ; if ( x < current . data ) current = current . left ; else current = current . right ; } // Insert new Node at the correct position if ( parent === null ) root = new Node ( x ); else if ( x < parent . data ) parent . left = new Node ( x ); else parent . right = new Node ( x ); } // Find maximum element in the path from an // ancestor to a node function maxInPath ( root x ) { let maxElement = - Infinity ; let current = root ; // Traverse the path from root to the target node 'x' while ( current !== null && current . data !== x ) { maxElement = Math . max ( maxElement current . data ); if ( x < current . data ) current = current . left ; else current = current . right ; } return Math . max ( maxElement x ); } // Find maximum element in the path between // two nodes in BST function findMaxElement ( root x y ) { let current = root ; // Find Lowest Common Ancestor (LCA) of x and y while (( x < current . data && y < current . data ) || ( x > current . data && y > current . data )) { if ( x < current . data && y < current . data ) current = current . left ; else if ( x > current . data && y > current . data ) current = current . right ; } // Find maximum elements in paths from LCA to // x and LCA to y return Math . max ( maxInPath ( current x ) maxInPath ( current y )); } const arr = [ 18 36 9 6 12 10 1 8 ]; const a = 1 b = 10 ; const root = new Node ( arr [ 0 ]); for ( let i = 1 ; i < arr . length ; i ++ ) { insertNode ( root arr [ i ]); } console . log ( findMaxElement ( root a b ));
Produktion
12Skapa frågesport
