Najděte všechny úhly daného trojúhelníku

Najděte všechny úhly daného trojúhelníku

Zadané souřadnice všech tří vrcholů trojúhelníku ve 2D rovině je úkolem najít všechny tři úhly.
Příklad:  
 

Input : A = (0 0) B = (0 1) C = (1 0) Output : 90 45 45 


 


K vyřešení tohoto problému používáme níže Zákon kosinusů
 

všechny úhly daného trojúhelníku


 

c^2 = a^2 + b^2 - 2(a)(b)(cos beta) 


Po opětovném uspořádání 
 

beta = acos( ( a^2 + b^2 - c^2 ) / (2ab) ) 


V trigonometrii zákon kosinů (také známý jako kosinusový vzorec nebo kosinusové pravidlo) spojuje délky stran trojúhelníku s kosinusem jednoho z jeho úhlů.
 

First calculate the length of all the sides. Then apply above formula to get all angles in radian. Then convert angles from radian into degrees. 


Níže je implementace výše uvedených kroků. 
 

C++
   // Code to find all three angles   // of a triangle given coordinate   // of all three vertices   #include          #include         // for pair   #include         // for math functions   using     namespace     std  ;   #define PI 3.1415926535   // returns square of distance b/w two points   int     lengthSquare  (  pair   <  int    int  >     X       pair   <  int    int  >     Y  )   {      int     xDiff     =     X  .  first     -     Y  .  first  ;      int     yDiff     =     X  .  second     -     Y  .  second  ;      return     xDiff  *  xDiff     +     yDiff  *  yDiff  ;   }   void     printAngle  (  pair   <  int    int  >     A       pair   <  int    int  >     B        pair   <  int    int  >     C  )   {      // Square of lengths be a2 b2 c2      int     a2     =     lengthSquare  (  B    C  );      int     b2     =     lengthSquare  (  A    C  );      int     c2     =     lengthSquare  (  A    B  );      // length of sides be a b c      float     a     =     sqrt  (  a2  );      float     b     =     sqrt  (  b2  );      float     c     =     sqrt  (  c2  );      // From Cosine law      float     alpha     =     acos  ((  b2     +     c2     -     a2  )  /  (  2  *  b  *  c  ));      float     beta     =     acos  ((  a2     +     c2     -     b2  )  /  (  2  *  a  *  c  ));      float     gamma     =     acos  ((  a2     +     b2     -     c2  )  /  (  2  *  a  *  b  ));      // Converting to degree      alpha     =     alpha     *     180     /     PI  ;      beta     =     beta     *     180     /     PI  ;      gamma     =     gamma     *     180     /     PI  ;      // printing all the angles      cout      < <     'alpha : '      < <     alpha      < <     endl  ;      cout      < <     'beta : '      < <     beta      < <     endl  ;      cout      < <     'gamma : '      < <     gamma      < <     endl  ;   }   // Driver code   int     main  ()   {      pair   <  int    int  >     A     =     make_pair  (  0    0  );      pair   <  int    int  >     B     =     make_pair  (  0    1  );      pair   <  int    int  >     C     =     make_pair  (  1    0  );      printAngle  (  A    B    C  );      return     0  ;   }   
Java
   // Java Code to find all three angles   // of a triangle given coordinate   // of all three vertices   import     java.awt.Point  ;   import static     java.lang.Math.PI  ;   import static     java.lang.Math.sqrt  ;   import static     java.lang.Math.acos  ;   class   Test   {      // returns square of distance b/w two points      static     int     lengthSquare  (  Point     p1       Point     p2  )      {      int     xDiff     =     p1  .  x  -     p2  .  x  ;      int     yDiff     =     p1  .  y  -     p2  .  y  ;      return     xDiff  *  xDiff     +     yDiff  *  yDiff  ;      }          static     void     printAngle  (  Point     A       Point     B        Point     C  )      {      // Square of lengths be a2 b2 c2      int     a2     =     lengthSquare  (  B    C  );      int     b2     =     lengthSquare  (  A    C  );      int     c2     =     lengthSquare  (  A    B  );          // length of sides be a b c      float     a     =     (  float  )  sqrt  (  a2  );      float     b     =     (  float  )  sqrt  (  b2  );      float     c     =     (  float  )  sqrt  (  c2  );          // From Cosine law      float     alpha     =     (  float  )     acos  ((  b2     +     c2     -     a2  )  /  (  2  *  b  *  c  ));      float     betta     =     (  float  )     acos  ((  a2     +     c2     -     b2  )  /  (  2  *  a  *  c  ));      float     gamma     =     (  float  )     acos  ((  a2     +     b2     -     c2  )  /  (  2  *  a  *  b  ));          // Converting to degree      alpha     =     (  float  )     (  alpha     *     180     /     PI  );      betta     =     (  float  )     (  betta     *     180     /     PI  );      gamma     =     (  float  )     (  gamma     *     180     /     PI  );          // printing all the angles      System  .  out  .  println  (  'alpha : '     +     alpha  );      System  .  out  .  println  (  'betta : '     +     betta  );      System  .  out  .  println  (  'gamma : '     +     gamma  );      }          // Driver method      public     static     void     main  (  String  []     args  )         {      Point     A     =     new     Point  (  0    0  );      Point     B     =     new     Point  (  0    1  );      Point     C     =     new     Point  (  1    0  );          printAngle  (  A    B    C  );      }   }   
Python3
   # Python3 code to find all three angles    # of a triangle given coordinate    # of all three vertices    import   math   # returns square of distance b/w two points    def   lengthSquare  (  X     Y  ):   xDiff   =   X  [  0  ]   -   Y  [  0  ]   yDiff   =   X  [  1  ]   -   Y  [  1  ]   return   xDiff   *   xDiff   +   yDiff   *   yDiff   def   printAngle  (  A     B     C  ):   # Square of lengths be a2 b2 c2    a2   =   lengthSquare  (  B     C  )   b2   =   lengthSquare  (  A     C  )   c2   =   lengthSquare  (  A     B  )   # length of sides be a b c    a   =   math  .  sqrt  (  a2  );   b   =   math  .  sqrt  (  b2  );   c   =   math  .  sqrt  (  c2  );   # From Cosine law    alpha   =   math  .  acos  ((  b2   +   c2   -   a2  )   /   (  2   *   b   *   c  ));   betta   =   math  .  acos  ((  a2   +   c2   -   b2  )   /   (  2   *   a   *   c  ));   gamma   =   math  .  acos  ((  a2   +   b2   -   c2  )   /   (  2   *   a   *   b  ));   # Converting to degree    alpha   =   alpha   *   180   /   math  .  pi  ;   betta   =   betta   *   180   /   math  .  pi  ;   gamma   =   gamma   *   180   /   math  .  pi  ;   # printing all the angles    print  (  'alpha :   %f  '   %  (  alpha  ))   print  (  'betta :   %f  '   %  (  betta  ))   print  (  'gamma :   %f  '   %  (  gamma  ))   # Driver code   A   =   (  0     0  )   B   =   (  0     1  )   C   =   (  1     0  )   printAngle  (  A     B     C  );   # This code is contributed    # by ApurvaRaj   
C#
   // C# Code to find all three angles   // of a triangle given coordinate   // of all three vertices   using     System  ;       class     GFG   {      class     Point      {      public     int     x       y  ;      public     Point  (  int     x       int     y  )      {      this  .  x     =     x  ;      this  .  y     =     y  ;      }      }          // returns square of distance b/w two points      static     int     lengthSquare  (  Point     p1       Point     p2  )      {      int     xDiff     =     p1  .  x     -     p2  .  x  ;      int     yDiff     =     p1  .  y     -     p2  .  y  ;      return     xDiff     *     xDiff     +     yDiff     *     yDiff  ;      }          static     void     printAngle  (  Point     A       Point     B       Point     C  )      {      // Square of lengths be a2 b2 c2      int     a2     =     lengthSquare  (  B       C  );      int     b2     =     lengthSquare  (  A       C  );      int     c2     =     lengthSquare  (  A       B  );          // length of sides be a b c      float     a     =     (  float  )  Math  .  Sqrt  (  a2  );      float     b     =     (  float  )  Math  .  Sqrt  (  b2  );      float     c     =     (  float  )  Math  .  Sqrt  (  c2  );          // From Cosine law      float     alpha     =     (  float  )     Math  .  Acos  ((  b2     +     c2     -     a2  )     /         (  2     *     b     *     c  ));      float     betta     =     (  float  )     Math  .  Acos  ((  a2     +     c2     -     b2  )     /         (  2     *     a     *     c  ));      float     gamma     =     (  float  )     Math  .  Acos  ((  a2     +     b2     -     c2  )     /         (  2     *     a     *     b  ));          // Converting to degree      alpha     =     (  float  )     (  alpha     *     180     /     Math  .  PI  );      betta     =     (  float  )     (  betta     *     180     /     Math  .  PI  );      gamma     =     (  float  )     (  gamma     *     180     /     Math  .  PI  );          // printing all the angles      Console  .  WriteLine  (  'alpha : '     +     alpha  );      Console  .  WriteLine  (  'betta : '     +     betta  );      Console  .  WriteLine  (  'gamma : '     +     gamma  );      }          // Driver Code      public     static     void     Main  (  String  []     args  )         {      Point     A     =     new     Point  (  0       0  );      Point     B     =     new     Point  (  0       1  );      Point     C     =     new     Point  (  1       0  );          printAngle  (  A       B       C  );      }   }   // This code is contributed by Rajput-Ji   
JavaScript
   // JavaScript program    // Code to find all three angles   // of a triangle given coordinate   // of all three vertices   // returns square of distance b/w two points   function     lengthSquare  (  X       Y  ){      let     xDiff     =     X  [  0  ]     -     Y  [  0  ];      let     yDiff     =     X  [  1  ]     -     Y  [  1  ];      return     xDiff  *  xDiff     +     yDiff  *  yDiff  ;   }   function     printAngle  (  A       B       C  ){          // Square of lengths be a2 b2 c2      let     a2     =     lengthSquare  (  B    C  );      let     b2     =     lengthSquare  (  A    C  );      let     c2     =     lengthSquare  (  A    B  );      // length of sides be a b c      let     a     =     Math  .  sqrt  (  a2  );      let     b     =     Math  .  sqrt  (  b2  );      let     c     =     Math  .  sqrt  (  c2  );      // From Cosine law      let     alpha     =     Math  .  acos  ((  b2     +     c2     -     a2  )  /  (  2  *  b  *  c  ));      let     beta     =     Math  .  acos  ((  a2     +     c2     -     b2  )  /  (  2  *  a  *  c  ));      let     gamma     =     Math  .  acos  ((  a2     +     b2     -     c2  )  /  (  2  *  a  *  b  ));      // Converting to degree      alpha     =     alpha     *     180     /     Math  .  PI  ;      beta     =     beta     *     180     /     Math  .  PI  ;      gamma     =     gamma     *     180     /     Math  .  PI  ;      // printing all the angles      console  .  log  (  'alpha : '       alpha  );      console  .  log  (  'beta : '       beta  );      console  .  log  (  'gamma : '       gamma  );   }   // Driver code   let     A     =     [  0       0  ];   let     B     =     [  0       1  ];   let     C     =     [  1       0  ];   printAngle  (  A    B    C  );   // The code is contributed by Gautam goel (guatamgoel962)   

výstup:  
 

alpha : 90 beta : 45 gamma : 45 

Časová náročnost: O(log(n)) od použití vestavěných funkcí sqrt

Pomocný prostor: O(1)

Odkaz
https://cs.wikipedia.org/wiki/Law_of_cosines
 

Vytvořit kvíz