Implementació de xifrat afí
El xifrat afí és un tipus de xifrat de substitució monoalfabètica en què cada lletra d'un alfabet s'assigna al seu equivalent numèric xifrat mitjançant una funció matemàtica senzilla i es torna a convertir en una lletra. La fórmula utilitzada significa que cada lletra es xifra amb una altra lletra i de nou, el que significa que el xifrat és essencialment un xifrat de substitució estàndard amb una regla que regula quina lletra va a quina.
Tot el procés es basa en treballar mòdul m (la longitud de l'alfabet utilitzat). En el xifrat afí, les lletres d'un alfabet de mida m s'assignen primer als nombres enters del rang 0 … m-1.
La "clau" del xifrat afí consta de 2 números que els anomenarem a i b. La discussió següent suposa l'ús d'un alfabet de 26 caràcters (m = 26). a s'ha de triar per ser relativament primer a m (és a dir, a no hauria de tenir factors en comú amb m).
Xifratge
Utilitza l'aritmètica modular per transformar l'enter al qual correspon cada lletra de text pla en un altre enter que correspongui a una lletra de text xifrat. La funció de xifratge per a una sola lletra és
E ( x ) = ( a x + b ) mod m modulus m: size of the alphabet a and b: key of the cipher. a must be chosen such that a and m are coprime.
Desxifrat
En desxifrar el text xifrat hem de realitzar les funcions oposades (o inverses) sobre el text xifrat per recuperar el text pla. Una vegada més, el primer pas és convertir cadascuna de les lletres del text xifrat en els seus valors enters. La funció de desxifrat és
D ( x ) = a^-1 ( x - b ) mod m a^-1 : modular multiplicative inverse of a modulo m. i.e. it satisfies the equation 1 = a a^-1 mod m .
Per trobar una inversa multiplicativa
Hem de trobar un nombre x tal que:
Si trobem el nombre x tal que l'equació és certa, aleshores x és la inversa de a i l'anomenem a^-1. La manera més fàcil de resoldre aquesta equació és cercar cadascun dels nombres de l'1 al 25 i veure quin satisfà l'equació.
[gxd] = gcd(am); % we can ignore g and d we dont need them x = mod(xm);
Si ara multipliqueu x i a i reduïu el resultat (mod 26) obtindreu la resposta 1. Recordeu que aquesta és només la definició d'una inversa, és a dir, si a*x = 1 (mod 26), aleshores x és una inversa de a (i a és una inversa de x)
Exemple:
Implementació:
C++ //CPP program to illustrate Affine Cipher #include using namespace std ; //Key values of a and b const int a = 17 ; const int b = 20 ; string encryptMessage ( string msg ) { ///Cipher Text initially empty string cipher = '' ; for ( int i = 0 ; i < msg . length (); i ++ ) { // Avoid space to be encrypted if ( msg [ i ] != ' ' ) /* applying encryption formula ( a x + b ) mod m {here x is msg[i] and m is 26} and added 'A' to bring it in range of ascii alphabet[ 65-90 | A-Z ] */ cipher = cipher + ( char ) (((( a * ( msg [ i ] - 'A' ) ) + b ) % 26 ) + 'A' ); else //else simply append space character cipher += msg [ i ]; } return cipher ; } string decryptCipher ( string cipher ) { string msg = '' ; int a_inv = 0 ; int flag = 0 ; //Find a^-1 (the multiplicative inverse of a //in the group of integers modulo m.) for ( int i = 0 ; i < 26 ; i ++ ) { flag = ( a * i ) % 26 ; //Check if (a*i)%26 == 1 //then i will be the multiplicative inverse of a if ( flag == 1 ) { a_inv = i ; } } for ( int i = 0 ; i < cipher . length (); i ++ ) { if ( cipher [ i ] != ' ' ) /*Applying decryption formula a^-1 ( x - b ) mod m {here x is cipher[i] and m is 26} and added 'A' to bring it in range of ASCII alphabet[ 65-90 | A-Z ] */ msg = msg + ( char ) ((( a_inv * (( cipher [ i ] + 'A' - b )) % 26 )) + 'A' ); else //else simply append space character msg += cipher [ i ]; } return msg ; } //Driver Program int main ( void ) { string msg = 'AFFINE CIPHER' ; //Calling encryption function string cipherText = encryptMessage ( msg ); cout < < 'Encrypted Message is : ' < < cipherText < < endl ; //Calling Decryption function cout < < 'Decrypted Message is: ' < < decryptCipher ( cipherText ); return 0 ; }
Java // Java program to illustrate Affine Cipher class GFG { // Key values of a and b static int a = 17 ; static int b = 20 ; static String encryptMessage ( char [] msg ) { /// Cipher Text initially empty String cipher = '' ; for ( int i = 0 ; i < msg . length ; i ++ ) { // Avoid space to be encrypted /* applying encryption formula ( a x + b ) mod m {here x is msg[i] and m is 26} and added 'A' to bring it in range of ascii alphabet[ 65-90 | A-Z ] */ if ( msg [ i ] != ' ' ) { cipher = cipher + ( char ) (((( a * ( msg [ i ] - 'A' )) + b ) % 26 ) + 'A' ); } else // else simply append space character { cipher += msg [ i ] ; } } return cipher ; } static String decryptCipher ( String cipher ) { String msg = '' ; int a_inv = 0 ; int flag = 0 ; //Find a^-1 (the multiplicative inverse of a //in the group of integers modulo m.) for ( int i = 0 ; i < 26 ; i ++ ) { flag = ( a * i ) % 26 ; // Check if (a*i)%26 == 1 // then i will be the multiplicative inverse of a if ( flag == 1 ) { a_inv = i ; } } for ( int i = 0 ; i < cipher . length (); i ++ ) { /*Applying decryption formula a^-1 ( x - b ) mod m {here x is cipher[i] and m is 26} and added 'A' to bring it in range of ASCII alphabet[ 65-90 | A-Z ] */ if ( cipher . charAt ( i ) != ' ' ) { msg = msg + ( char ) ((( a_inv * (( cipher . charAt ( i ) + 'A' - b )) % 26 )) + 'A' ); } else //else simply append space character { msg += cipher . charAt ( i ); } } return msg ; } // Driver code public static void main ( String [] args ) { String msg = 'AFFINE CIPHER' ; // Calling encryption function String cipherText = encryptMessage ( msg . toCharArray ()); System . out . println ( 'Encrypted Message is : ' + cipherText ); // Calling Decryption function System . out . println ( 'Decrypted Message is: ' + decryptCipher ( cipherText )); } } // This code contributed by Rajput-Ji
Python # Implementation of Affine Cipher in Python # Extended Euclidean Algorithm for finding modular inverse # eg: modinv(7 26) = 15 def egcd ( a b ): x y u v = 0 1 1 0 while a != 0 : q r = b // a b % a m n = x - u * q y - v * q b a x y u v = a r u v m n gcd = b return gcd x y def modinv ( a m ): gcd x y = egcd ( a m ) if gcd != 1 : return None # modular inverse does not exist else : return x % m # affine cipher encryption function # returns the cipher text def affine_encrypt ( text key ): ''' C = (a*P + b) % 26 ''' return '' . join ([ chr ((( key [ 0 ] * ( ord ( t ) - ord ( 'A' )) + key [ 1 ] ) % 26 ) + ord ( 'A' )) for t in text . upper () . replace ( ' ' '' ) ]) # affine cipher decryption function # returns original text def affine_decrypt ( cipher key ): ''' P = (a^-1 * (C - b)) % 26 ''' return '' . join ([ chr ((( modinv ( key [ 0 ] 26 ) * ( ord ( c ) - ord ( 'A' ) - key [ 1 ])) % 26 ) + ord ( 'A' )) for c in cipher ]) # Driver Code to test the above functions def main (): # declaring text and key text = 'AFFINE CIPHER' key = [ 17 20 ] # calling encryption function affine_encrypted_text = affine_encrypt ( text key ) print ( 'Encrypted Text: {} ' . format ( affine_encrypted_text )) # calling decryption function print ( 'Decrypted Text: {} ' . format ( affine_decrypt ( affine_encrypted_text key ) )) if __name__ == '__main__' : main () # This code is contributed by # Bhushan Borole
C# // C# program to illustrate Affine Cipher using System ; class GFG { // Key values of a and b static int a = 17 ; static int b = 20 ; static String encryptMessage ( char [] msg ) { /// Cipher Text initially empty String cipher = '' ; for ( int i = 0 ; i < msg . Length ; i ++ ) { // Avoid space to be encrypted /* applying encryption formula ( a x + b ) mod m {here x is msg[i] and m is 26} and added 'A' to bring it in range of ascii alphabet[ 65-90 | A-Z ] */ if ( msg [ i ] != ' ' ) { cipher = cipher + ( char ) (((( a * ( msg [ i ] - 'A' )) + b ) % 26 ) + 'A' ); } else // else simply append space character { cipher += msg [ i ]; } } return cipher ; } static String decryptCipher ( String cipher ) { String msg = '' ; int a_inv = 0 ; int flag = 0 ; //Find a^-1 (the multiplicative inverse of a //in the group of integers modulo m.) for ( int i = 0 ; i < 26 ; i ++ ) { flag = ( a * i ) % 26 ; // Check if (a*i)%26 == 1 // then i will be the multiplicative inverse of a if ( flag == 1 ) { a_inv = i ; } } for ( int i = 0 ; i < cipher . Length ; i ++ ) { /*Applying decryption formula a^-1 ( x - b ) mod m {here x is cipher[i] and m is 26} and added 'A' to bring it in range of ASCII alphabet[ 65-90 | A-Z ] */ if ( cipher [ i ] != ' ' ) { msg = msg + ( char ) ((( a_inv * (( cipher [ i ] + 'A' - b )) % 26 )) + 'A' ); } else //else simply append space character { msg += cipher [ i ]; } } return msg ; } // Driver code public static void Main ( String [] args ) { String msg = 'AFFINE CIPHER' ; // Calling encryption function String cipherText = encryptMessage ( msg . ToCharArray ()); Console . WriteLine ( 'Encrypted Message is : ' + cipherText ); // Calling Decryption function Console . WriteLine ( 'Decrypted Message is: ' + decryptCipher ( cipherText )); } } /* This code contributed by PrinciRaj1992 */
JavaScript //Javascript program to illustrate Affine Cipher //Key values of a and b let a = 17 ; let b = 20 ; function encryptMessage ( msg ) { ///Cipher Text initially empty let cipher = '' ; for ( let i = 0 ; i < msg . length ; i ++ ) { // Avoid space to be encrypted if ( msg [ i ] != ' ' ) /* applying encryption formula ( a x + b ) mod m {here x is msg[i] and m is 26} and added 'A' to bring it in range of ascii alphabet[ 65-90 | A-Z ] */ cipher = cipher + String . fromCharCode (((( a * ( msg [ i ]. charCodeAt ( 0 ) - 65 ) ) + b ) % 26 ) + 65 ); else //else simply append space character cipher += msg [ i ]; } return cipher ; } function decryptCipher ( cipher ) { let msg = '' ; let a_inv = 0 ; let flag = 0 ; //Find a^-1 (the multiplicative inverse of a //in the group of integers modulo m.) for ( let i = 0 ; i < 26 ; i ++ ) { flag = ( a * i ) % 26 ; //Check if (a*i)%26 == 1 //then i will be the multiplicative inverse of a if ( flag == 1 ) { a_inv = i ; } } for ( let i = 0 ; i < cipher . length ; i ++ ) { if ( cipher [ i ] != ' ' ) /*Applying decryption formula a^-1 ( x - b ) mod m {here x is cipher[i] and m is 26} and added 'A' to bring it in range of ASCII alphabet[ 65-90 | A-Z ] */ msg = msg + String . fromCharCode ((( a_inv * (( cipher [ i ]. charCodeAt ( 0 ) + 65 - b )) % 26 )) + 65 ); else //else simply append space character msg += cipher [ i ]; } return msg ; } //Driver Program let msg = 'AFFINE CIPHER' ; //Calling encryption function let cipherText = encryptMessage ( msg ); console . log ( 'Encrypted Message is : ' + cipherText ); //Calling Decryption function console . log ( 'Decrypted Message is: ' + decryptCipher ( cipherText )); // The code is contributed by Arushi Jindal.
Sortida
Encrypted Message is : UBBAHK CAPJKX Decrypted Message is: AFFINE CIPHER
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