أطول مسار في الرسم البياني الحلقي الموجه | مجموعة 2

بالنظر إلى الرسم البياني الحلقي الموجه الموزون (DAG) وقمة المصدر فيه، يمكنك العثور على أطول المسافات من قمة المصدر إلى جميع القمم الأخرى في الرسم البياني المحدد.

لقد ناقشنا بالفعل كيف يمكننا العثور عليها أطول مسار في الرسم البياني الحلقي الموجه (DAG) في المجموعة 1. سنناقش في هذا المنشور حلاً آخر مثيرًا للاهتمام للعثور على أطول مسار لـ DAG يستخدم الخوارزمية للبحث أقصر مسار في DAG .

الفكرة هي أن أبطل أوزان المسار وأوجد أقصر مسار في الرسم البياني . أطول مسار بين رأسين محددين s وt في الرسم البياني الموزون G هو نفس المسار الأقصر في الرسم البياني G' المشتق من G عن طريق تغيير كل وزن إلى نفيه. لذلك، إذا كان من الممكن العثور على أقصر المسارات في G'، فيمكن أيضًا العثور على المسارات الأطول في G. 
فيما يلي عملية خطوة بخطوة للعثور على أطول المسارات -

نقوم بتغيير وزن كل حافة من الرسم البياني المعطى إلى نفيها وتهيئة المسافات إلى جميع القمم على أنها لا نهائية والمسافة إلى المصدر كـ 0 ثم نجد فرزًا طوبولوجيًا للرسم البياني الذي يمثل ترتيبًا خطيًا للرسم البياني. عندما نفكر في قمة u بالترتيب الطوبولوجي، فمن المؤكد أننا أخذنا في الاعتبار كل حافة واردة إليها. أي لقد وجدنا بالفعل أقصر مسار لتلك القمة ويمكننا استخدام هذه المعلومات لتحديث المسار الأقصر لجميع القمم المجاورة لها. بمجرد حصولنا على ترتيب طوبولوجي، نقوم بمعالجة جميع القمم واحدًا تلو الآخر بالترتيب الطوبولوجي. لكل قمة تتم معالجتها، نقوم بتحديث مسافات القمة المجاورة لها باستخدام أقصر مسافة للقمة الحالية من قمة المصدر ووزن الحافة. أي. 

for every adjacent vertex v of every vertex u in topological order if (dist[v] > dist[u] + weight(u v)) dist[v] = dist[u] + weight(u v) 

بمجرد العثور على جميع المسارات الأقصر من قمة المصدر، ستكون المسارات الأطول مجرد إلغاء لأقصر المسارات.

وفيما يلي تنفيذ النهج المذكور أعلاه:

C++
   // A C++ program to find single source longest distances   // in a DAG   #include          using     namespace     std  ;   // Graph is represented using adjacency list. Every node of   // adjacency list contains vertex number of the vertex to   // which edge connects. It also contains weight of the edge   class     AdjListNode   {      int     v  ;      int     weight  ;   public  :      AdjListNode  (  int     _v       int     _w  )      {      v     =     _v  ;      weight     =     _w  ;      }      int     getV  ()      {      return     v  ;      }      int     getWeight  ()      {      return     weight  ;      }   };   // Graph class represents a directed graph using adjacency   // list representation   class     Graph   {      int     V  ;     // No. of vertices      // Pointer to an array containing adjacency lists      list   <  AdjListNode  >*     adj  ;      // This function uses DFS      void     longestPathUtil  (  int       vector   <  bool  >     &       stack   <  int  >     &  );   public  :      Graph  (  int  );     // Constructor      ~  Graph  ();     // Destructor      // function to add an edge to graph      void     addEdge  (  int       int       int  );      void     longestPath  (  int  );   };   Graph  ::  Graph  (  int     V  )     // Constructor   {      this  ->  V     =     V  ;      adj     =     new     list   <  AdjListNode  >  [  V  ];   }   Graph  ::~  Graph  ()     // Destructor   {      delete  []     adj  ;   }   void     Graph  ::  addEdge  (  int     u       int     v       int     weight  )   {      AdjListNode     node  (  v       weight  );      adj  [  u  ].  push_back  (  node  );     // Add v to u's list   }   // A recursive function used by longestPath. See below   // link for details.   // https://www.geeksforgeeks.org/dsa/topological-sorting/   void     Graph  ::  longestPathUtil  (  int     v       vector   <  bool  >     &  visited        stack   <  int  >     &  Stack  )   {      // Mark the current node as visited      visited  [  v  ]     =     true  ;      // Recur for all the vertices adjacent to this vertex      for     (  AdjListNode     node     :     adj  [  v  ])      {      if     (  !  visited  [  node  .  getV  ()])      longestPathUtil  (  node  .  getV  ()     visited       Stack  );      }      // Push current vertex to stack which stores topological      // sort      Stack  .  push  (  v  );   }   // The function do Topological Sort and finds longest   // distances from given source vertex   void     Graph  ::  longestPath  (  int     s  )   {      // Initialize distances to all vertices as infinite and      // distance to source as 0      int     dist  [  V  ];      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )      dist  [  i  ]     =     INT_MAX  ;      dist  [  s  ]     =     0  ;      stack   <  int  >     Stack  ;      // Mark all the vertices as not visited      vector   <  bool  >     visited  (  V       false  );      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )      if     (  visited  [  i  ]     ==     false  )      longestPathUtil  (  i       visited       Stack  );      // Process vertices in topological order      while     (  !  Stack  .  empty  ())      {      // Get the next vertex from topological order      int     u     =     Stack  .  top  ();      Stack  .  pop  ();      if     (  dist  [  u  ]     !=     INT_MAX  )      {      // Update distances of all adjacent vertices      // (edge from u -> v exists)      for     (  AdjListNode     v     :     adj  [  u  ])      {      // consider negative weight of edges and      // find shortest path      if     (  dist  [  v  .  getV  ()]     >     dist  [  u  ]     +     v  .  getWeight  ()     *     -1  )      dist  [  v  .  getV  ()]     =     dist  [  u  ]     +     v  .  getWeight  ()     *     -1  ;      }      }      }      // Print the calculated longest distances      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )      {      if     (  dist  [  i  ]     ==     INT_MAX  )      cout      < <     'INT_MIN '  ;      else      cout      < <     (  dist  [  i  ]     *     -1  )      < <     ' '  ;      }   }   // Driver code   int     main  ()   {      Graph     g  (  6  );      g  .  addEdge  (  0       1       5  );      g  .  addEdge  (  0       2       3  );      g  .  addEdge  (  1       3       6  );      g  .  addEdge  (  1       2       2  );      g  .  addEdge  (  2       4       4  );      g  .  addEdge  (  2       5       2  );      g  .  addEdge  (  2       3       7  );      g  .  addEdge  (  3       5       1  );      g  .  addEdge  (  3       4       -1  );      g  .  addEdge  (  4       5       -2  );      int     s     =     1  ;      cout      < <     'Following are longest distances from '       < <     'source vertex '      < <     s      < <     '   n  '  ;      g  .  longestPath  (  s  );      return     0  ;   }   
Python3
   # A Python3 program to find single source    # longest distances in a DAG   import   sys   def   addEdge  (  u     v     w  ):   global   adj   adj  [  u  ]  .  append  ([  v     w  ])   # A recursive function used by longestPath.    # See below link for details.   # https:#www.geeksforgeeks.org/topological-sorting/   def   longestPathUtil  (  v  ):   global   visited     adj    Stack   visited  [  v  ]   =   1   # Recur for all the vertices adjacent   # to this vertex   for   node   in   adj  [  v  ]:   if   (  not   visited  [  node  [  0  ]]):   longestPathUtil  (  node  [  0  ])   # Push current vertex to stack which    # stores topological sort   Stack  .  append  (  v  )   # The function do Topological Sort and finds   # longest distances from given source vertex   def   longestPath  (  s  ):   # Initialize distances to all vertices    # as infinite and   global   visited     Stack     adj    V   dist   =   [  sys  .  maxsize   for   i   in   range  (  V  )]   # for (i = 0 i  < V i++)   # dist[i] = INT_MAX   dist  [  s  ]   =   0   for   i   in   range  (  V  ):   if   (  visited  [  i  ]   ==   0  ):   longestPathUtil  (  i  )   # print(Stack)   while   (  len  (  Stack  )   >   0  ):   # Get the next vertex from topological order   u   =   Stack  [  -  1  ]   del   Stack  [  -  1  ]   if   (  dist  [  u  ]   !=   sys  .  maxsize  ):   # Update distances of all adjacent vertices   # (edge from u -> v exists)   for   v   in   adj  [  u  ]:   # Consider negative weight of edges and   # find shortest path   if   (  dist  [  v  [  0  ]]   >   dist  [  u  ]   +   v  [  1  ]   *   -  1  ):   dist  [  v  [  0  ]]   =   dist  [  u  ]   +   v  [  1  ]   *   -  1   # Print the calculated longest distances   for   i   in   range  (  V  ):   if   (  dist  [  i  ]   ==   sys  .  maxsize  ):   print  (  'INT_MIN '     end   =   ' '  )   else  :   print  (  dist  [  i  ]   *   (  -  1  )   end   =   ' '  )   # Driver code   if   __name__   ==   '__main__'  :   V   =   6   visited   =   [  0   for   i   in   range  (  7  )]   Stack   =   []   adj   =   [[]   for   i   in   range  (  7  )]   addEdge  (  0     1     5  )   addEdge  (  0     2     3  )   addEdge  (  1     3     6  )   addEdge  (  1     2     2  )   addEdge  (  2     4     4  )   addEdge  (  2     5     2  )   addEdge  (  2     3     7  )   addEdge  (  3     5     1  )   addEdge  (  3     4     -  1  )   addEdge  (  4     5     -  2  )   s   =   1   print  (  'Following are longest distances from source vertex'     s  )   longestPath  (  s  )   # This code is contributed by mohit kumar 29   
C#
   // C# program to find single source longest distances   // in a DAG   using     System  ;   using     System.Collections.Generic  ;   // Graph is represented using adjacency list. Every node of   // adjacency list contains vertex number of the vertex to   // which edge connects. It also contains weight of the edge   class     AdjListNode     {      private     int     v  ;      private     int     weight  ;      public     AdjListNode  (  int     _v       int     _w  )      {      v     =     _v  ;      weight     =     _w  ;      }      public     int     getV  ()     {     return     v  ;     }      public     int     getWeight  ()     {     return     weight  ;     }   }   // Graph class represents a directed graph using adjacency   // list representation   class     Graph     {      private     int     V  ;     // No. of vertices      // Pointer to an array containing adjacency lists      private     List   <  AdjListNode  >  []     adj  ;      public     Graph  (  int     v  )     // Constructor      {      V     =     v  ;      adj     =     new     List   <  AdjListNode  >  [     v     ];      for     (  int     i     =     0  ;     i      <     v  ;     i  ++  )      adj  [  i  ]     =     new     List   <  AdjListNode  >  ();      }      public     void     AddEdge  (  int     u       int     v       int     weight  )      {      AdjListNode     node     =     new     AdjListNode  (  v       weight  );      adj  [  u  ].  Add  (  node  );     // Add v to u's list      }      // A recursive function used by longestPath. See below      // link for details.      // https://www.geeksforgeeks.org/dsa/topological-sorting/      private     void     LongestPathUtil  (  int     v       bool  []     visited        Stack   <  int  >     stack  )      {      // Mark the current node as visited      visited  [  v  ]     =     true  ;      // Recur for all the vertices adjacent to this      // vertex      foreach  (  AdjListNode     node     in     adj  [  v  ])      {      if     (  !  visited  [  node  .  getV  ()])      LongestPathUtil  (  node  .  getV  ()     visited        stack  );      }      // Push current vertex to stack which stores      // topological sort      stack  .  Push  (  v  );      }      // The function do Topological Sort and finds longest      // distances from given source vertex      public     void     LongestPath  (  int     s  )      {          // Initialize distances to all vertices as infinite      // and distance to source as 0      int  []     dist     =     new     int  [  V  ];      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )      dist  [  i  ]     =     Int32  .  MaxValue  ;      dist  [  s  ]     =     0  ;      Stack   <  int  >     stack     =     new     Stack   <  int  >  ();      // Mark all the vertices as not visited      bool  []     visited     =     new     bool  [  V  ];      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )     {      if     (  visited  [  i  ]     ==     false  )      LongestPathUtil  (  i       visited       stack  );      }      // Process vertices in topological order      while     (  stack  .  Count     >     0  )     {      // Get the next vertex from topological order      int     u     =     stack  .  Pop  ();      if     (  dist  [  u  ]     !=     Int32  .  MaxValue  )     {      // Update distances of all adjacent vertices      // (edge from u -> v exists)      foreach  (  AdjListNode     v     in     adj  [  u  ])      {      // consider negative weight of edges and      // find shortest path      if     (  dist  [  v  .  getV  ()]      >     dist  [  u  ]     +     v  .  getWeight  ()     *     -  1  )      dist  [  v  .  getV  ()]      =     dist  [  u  ]     +     v  .  getWeight  ()     *     -  1  ;      }      }      }      // Print the calculated longest distances      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )     {      if     (  dist  [  i  ]     ==     Int32  .  MaxValue  )      Console  .  Write  (  'INT_MIN '  );      else      Console  .  Write  (  '{0} '       dist  [  i  ]     *     -  1  );      }      Console  .  WriteLine  ();      }   }   public     class     GFG     {      // Driver code      static     void     Main  (  string  []     args  )      {      Graph     g     =     new     Graph  (  6  );      g  .  AddEdge  (  0       1       5  );      g  .  AddEdge  (  0       2       3  );      g  .  AddEdge  (  1       3       6  );      g  .  AddEdge  (  1       2       2  );      g  .  AddEdge  (  2       4       4  );      g  .  AddEdge  (  2       5       2  );      g  .  AddEdge  (  2       3       7  );      g  .  AddEdge  (  3       5       1  );      g  .  AddEdge  (  3       4       -  1  );      g  .  AddEdge  (  4       5       -  2  );      int     s     =     1  ;      Console  .  WriteLine  (      'Following are longest distances from source vertex {0} '        s  );      g  .  LongestPath  (  s  );      }   }   // This code is contributed by cavi4762.   
Java
   // A Java program to find single source longest distances   // in a DAG   import     java.util.*  ;   // Graph is represented using adjacency list. Every   // node of adjacency list contains vertex number of   // the vertex to which edge connects. It also   // contains weight of the edge   class   AdjListNode     {      private     int     v  ;      private     int     weight  ;      AdjListNode  (  int     _v       int     _w  )      {      v     =     _v  ;      weight     =     _w  ;      }      int     getV  ()     {     return     v  ;     }      int     getWeight  ()     {     return     weight  ;     }   }   // Class to represent a graph using adjacency list   // representation   public     class   GFG     {      int     V  ;     // No. of vertices'      // Pointer to an array containing adjacency lists      ArrayList   <  AdjListNode  >[]     adj  ;      @SuppressWarnings  (  'unchecked'  )      GFG  (  int     V  )     // Constructor      {      this  .  V     =     V  ;      adj     =     new     ArrayList  [  V  ]  ;      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )     {      adj  [  i  ]     =     new     ArrayList   <>  ();      }      }      void     addEdge  (  int     u       int     v       int     weight  )      {      AdjListNode     node     =     new     AdjListNode  (  v       weight  );      adj  [  u  ]  .  add  (  node  );     // Add v to u's list      }      // A recursive function used by longestPath. See      // below link for details https://      // www.geeksforgeeks.org/topological-sorting/      void     topologicalSortUtil  (  int     v       boolean     visited  []        Stack   <  Integer  >     stack  )      {      // Mark the current node as visited      visited  [  v  ]     =     true  ;      // Recur for all the vertices adjacent to this      // vertex      for     (  int     i     =     0  ;     i      <     adj  [  v  ]  .  size  ();     i  ++  )     {      AdjListNode     node     =     adj  [  v  ]  .  get  (  i  );      if     (  !  visited  [  node  .  getV  ()  ]  )      topologicalSortUtil  (  node  .  getV  ()     visited        stack  );      }      // Push current vertex to stack which stores      // topological sort      stack  .  push  (  v  );      }      // The function to find Smallest distances from a      // given vertex. It uses recursive      // topologicalSortUtil() to get topological sorting.      void     longestPath  (  int     s  )      {      Stack   <  Integer  >     stack     =     new     Stack   <  Integer  >  ();      int     dist  []     =     new     int  [  V  ]  ;      // Mark all the vertices as not visited      boolean     visited  []     =     new     boolean  [  V  ]  ;      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )      visited  [  i  ]     =     false  ;      // Call the recursive helper function to store      // Topological Sort starting from all vertices      // one by one      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )      if     (  visited  [  i  ]     ==     false  )      topologicalSortUtil  (  i       visited       stack  );      // Initialize distances to all vertices as      // infinite and distance to source as 0      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )      dist  [  i  ]     =     Integer  .  MAX_VALUE  ;      dist  [  s  ]     =     0  ;      // Process vertices in topological order      while     (  stack  .  isEmpty  ()     ==     false  )     {      // Get the next vertex from topological      // order      int     u     =     stack  .  peek  ();      stack  .  pop  ();      // Update distances of all adjacent vertices      if     (  dist  [  u  ]     !=     Integer  .  MAX_VALUE  )     {      for     (  AdjListNode     v     :     adj  [  u  ]  )     {      if     (  dist  [  v  .  getV  ()  ]      >     dist  [  u  ]     +     v  .  getWeight  ()     *     -  1  )      dist  [  v  .  getV  ()  ]      =     dist  [  u  ]     +     v  .  getWeight  ()     *     -  1  ;      }      }      }      // Print the calculated longest distances      for     (  int     i     =     0  ;     i      <     V  ;     i  ++  )      if     (  dist  [  i  ]     ==     Integer  .  MAX_VALUE  )      System  .  out  .  print  (  'INF '  );      else      System  .  out  .  print  (  dist  [  i  ]     *     -  1     +     ' '  );      }      // Driver program to test above functions      public     static     void     main  (  String     args  []  )      {      // Create a graph given in the above diagram.      // Here vertex numbers are 0 1 2 3 4 5 with      // following mappings:      // 0=r 1=s 2=t 3=x 4=y 5=z      GFG     g     =     new     GFG  (  6  );      g  .  addEdge  (  0       1       5  );      g  .  addEdge  (  0       2       3  );      g  .  addEdge  (  1       3       6  );      g  .  addEdge  (  1       2       2  );      g  .  addEdge  (  2       4       4  );      g  .  addEdge  (  2       5       2  );      g  .  addEdge  (  2       3       7  );      g  .  addEdge  (  3       5       1  );      g  .  addEdge  (  3       4       -  1  );      g  .  addEdge  (  4       5       -  2  );      int     s     =     1  ;      System  .  out  .  print  (      'Following are longest distances from source vertex '      +     s     +     ' n'  );      g  .  longestPath  (  s  );      }   }   // This code is contributed by Prithi_Dey   
JavaScript
   class     AdjListNode     {      constructor  (  v       weight  )     {      this  .  v     =     v  ;      this  .  weight     =     weight  ;      }      getV  ()     {     return     this  .  v  ;     }      getWeight  ()     {     return     this  .  weight  ;     }   }   class     GFG     {      constructor  (  V  )     {      this  .  V     =     V  ;      this  .  adj     =     new     Array  (  V  );      for     (  let     i     =     0  ;     i      <     V  ;     i  ++  )     {      this  .  adj  [  i  ]     =     new     Array  ();      }      }      addEdge  (  u       v       weight  )     {      let     node     =     new     AdjListNode  (  v       weight  );      this  .  adj  [  u  ].  push  (  node  );      }      topologicalSortUtil  (  v       visited       stack  )     {      visited  [  v  ]     =     true  ;      for     (  let     i     =     0  ;     i      <     this  .  adj  [  v  ].  length  ;     i  ++  )     {      let     node     =     this  .  adj  [  v  ][  i  ];      if     (  !  visited  [  node  .  getV  ()])     {      this  .  topologicalSortUtil  (  node  .  getV  ()     visited       stack  );      }      }      stack  .  push  (  v  );      }      longestPath  (  s  )     {      let     stack     =     new     Array  ();      let     dist     =     new     Array  (  this  .  V  );      let     visited     =     new     Array  (  this  .  V  );      for     (  let     i     =     0  ;     i      <     this  .  V  ;     i  ++  )     {      visited  [  i  ]     =     false  ;      }      for     (  let     i     =     0  ;     i      <     this  .  V  ;     i  ++  )     {      if     (  !  visited  [  i  ])     {      this  .  topologicalSortUtil  (  i       visited       stack  );      }      }      for     (  let     i     =     0  ;     i      <     this  .  V  ;     i  ++  )     {      dist  [  i  ]     =     Number  .  MAX_SAFE_INTEGER  ;      }              dist  [  s  ]     =     0  ;      let     u     =     stack  .  pop  ();      while     (  stack  .  length     >     0  )     {      u     =     stack  .  pop  ();      if     (  dist  [  u  ]     !==     Number  .  MAX_SAFE_INTEGER  )     {      for     (  let     v     of     this  .  adj  [  u  ])     {      if     (  dist  [  v  .  getV  ()]     >     dist  [  u  ]     +     v  .  getWeight  ()     *     -  1  )     {      dist  [  v  .  getV  ()]     =     dist  [  u  ]     +     v  .  getWeight  ()     *     -  1  ;      }      }      }   }              for     (  let     i     =     0  ;     i      <     this  .  V  ;     i  ++  )     {      if     (  dist  [  i  ]     ===     Number  .  MAX_SAFE_INTEGER  )     {      console  .  log  (  'INF'  );      }      else     {      console  .  log  (  dist  [  i  ]     *     -  1  );      }      }      }   }   let     g     =     new     GFG  (  6  );   g  .  addEdge  (  0       1       5  );   g  .  addEdge  (  0       2       3  );   g  .  addEdge  (  1       3       6  );   g  .  addEdge  (  1       2       2  );   g  .  addEdge  (  2       4       4  );   g  .  addEdge  (  2       5       2  );   g  .  addEdge  (  2       3       7  );   g  .  addEdge  (  3       5       1  );   g  .  addEdge  (  3       4       -  1  );   g  .  addEdge  (  4       5       -  2  );   console  .  log  (  'Longest distances from the vertex 1 : '  );   g  .  longestPath  (  1  );   //this code is contributed by devendra   

الإخراج
Following are longest distances from source vertex 1 INT_MIN 0 2 9 8 10  

تعقيد الوقت : التعقيد الزمني للفرز الطوبولوجي هو يا (الخامس + ه). بعد العثور على الترتيب الطوبولوجي، تقوم الخوارزمية بمعالجة جميع القمم ولكل قمة تقوم بتشغيل حلقة لجميع القمم المجاورة. نظرًا لأن إجمالي القمم المجاورة في الرسم البياني هو O(E)، فإن الحلقة الداخلية تعمل O(V + E) مرات. وبالتالي فإن التعقيد الزمني الإجمالي لهذه الخوارزمية هو O(V + E).

تعقيد الفضاء:
التعقيد المكاني للخوارزمية المذكورة أعلاه هو يا (الخامس). نقوم بتخزين مصفوفة الإخراج ومكدس للفرز الطوبولوجي.