حذف منتصف القائمة المرتبطة

حذف منتصف القائمة المرتبطة

بالنظر إلى قائمة مرتبطة بشكل فردي، تكون المهمة هي حذف العقدة الوسطى من القائمة.

  • إذا كانت القائمة تحتوي على عدد زوجي من العقد، فسيكون هناك عقدتان وسطيان. في هذه الحالة، قم بحذف العقدة الوسطى الثانية.
  • إذا كانت القائمة المرتبطة تتكون من عقدة واحدة فقط، فسيتم إرجاع NULL.

مثال:

مدخل: القائمة المرتبطة: 1-> 2-> 3-> 4-> 5
الإخراج: 1->2->4->5
توضيح:

حذف منتصف القائمة المرتبطة

مدخل: القائمة المرتبطة: 2-> 4-> 6-> 7-> 5-> 1
الإخراج: 2->4->6->5->1
الشرح:

حذف منتصف القائمة المرتبطة

مدخل: القائمة المرتبطة: 7
الإخراج:

جدول المحتويات

[نهج ساذج] استخدام اجتياز ثنائي المسار - وقت O(n) ومساحة O(1).

الفكرة الأساسية وراء هذا الأسلوب هي اجتياز القائمة المرتبطة بالكامل أولاً لحساب العدد الإجمالي للعقد. بمجرد أن نعرف العدد الإجمالي للعقد يمكننا حساب موضع العقدة الوسطى الموجودة في الفهرس ن/2 (حيث n هو العدد الإجمالي للعقد). ثم انتقل إلى القائمة المرتبطة مرة أخرى ولكن هذه المرة نتوقف مباشرة قبل العقدة الوسطى. وبمجرد الوصول إلى هناك، نقوم بتعديل المؤشر التالي للعقدة قبل العقدة الوسطى بحيث يتخطى العقدة الوسطى ويشير مباشرة إلى العقدة التي تليها

وفيما يلي تنفيذ النهج المذكور أعلاه:

C++
   // C++ program to delete middle of a linked list   #include          using     namespace     std  ;   struct     Node     {      int     data  ;      Node  *     next  ;      Node  (  int     x  ){      data     =     x  ;      next     =     nullptr  ;      }   };   // Function to delete middle node from linked list.   Node  *     deleteMid  (  Node  *     head  )     {      // Edge case: return nullptr if there is only      // one node.      if     (  head  ->  next     ==     nullptr  )      return     nullptr  ;      int     count     =     0  ;      Node     *  p1     =     head       *  p2     =     head  ;      // First pass count the number of nodes      // in the linked list using 'p1'.      while     (  p1     !=     nullptr  )     {      count  ++  ;      p1     =     p1  ->  next  ;      }      // Get the index of the node to be deleted.      int     middleIndex     =     count     /     2  ;      // Second pass let 'p2' move toward the predecessor      // of the middle node.      for     (  int     i     =     0  ;     i      <     middleIndex     -     1  ;     ++  i  )      p2     =     p2  ->  next  ;      // Delete the middle node and return 'head'.      p2  ->  next     =     p2  ->  next  ->  next  ;      return     head  ;   }   void     printList  (  Node  *     head  )     {      Node  *     temp     =     head  ;      while     (  temp     !=     nullptr  )     {      cout      < <     temp  ->  data      < <     ' -> '  ;      temp     =     temp  ->  next  ;      }      cout      < <     'nullptr'      < <     endl  ;   }   int     main  ()     {      // Create a static hardcoded linked list:      // 1 -> 2 -> 3 -> 4 -> 5.      Node  *     head     =     new     Node  (  1  );      head  ->  next     =     new     Node  (  2  );      head  ->  next  ->  next     =     new     Node  (  3  );      head  ->  next  ->  next  ->  next     =     new     Node  (  4  );      head  ->  next  ->  next  ->  next  ->  next     =     new     Node  (  5  );      cout      < <     'Original Linked List: '  ;      printList  (  head  );      // Delete the middle node.      head     =     deleteMid  (  head  );      cout      < <     'Linked List after deleting the middle node: '  ;      printList  (  head  );      return     0  ;   }   
C
   // C program to delete middle of a linked list   #include         #include         struct     Node     {      int     data  ;      struct     Node  *     next  ;   };   // Function to delete middle node from linked list.   struct     Node  *     deleteMid  (  struct     Node  *     head  )     {      // Edge case: return NULL if there is only      // one node.      if     (  head  ->  next     ==     NULL  )      return     NULL  ;      int     count     =     0  ;      struct     Node     *  p1     =     head       *  p2     =     head  ;      // First pass count the number of nodes      // in the linked list using 'p1'.      while     (  p1     !=     NULL  )     {      count  ++  ;      p1     =     p1  ->  next  ;      }      // Get the index of the node to be deleted.      int     middleIndex     =     count     /     2  ;      // Second pass let 'p2' move toward the predecessor      // of the middle node.      for     (  int     i     =     0  ;     i      <     middleIndex     -     1  ;     ++  i  )      p2     =     p2  ->  next  ;      // Delete the middle node and return 'head'.      p2  ->  next     =     p2  ->  next  ->  next  ;      return     head  ;   }   void     printList  (  struct     Node  *     head  )     {      struct     Node  *     temp     =     head  ;      while     (  temp     !=     NULL  )     {      printf  (  '%d -> '       temp  ->  data  );      temp     =     temp  ->  next  ;      }      printf  (  'NULL  n  '  );   }   struct     Node  *     newNode  (  int     x  )     {      struct     Node  *     temp     =         (  struct     Node  *  )  malloc  (  sizeof  (  struct     Node  ));      temp  ->  data     =     x  ;      temp  ->  next     =     NULL  ;      return     temp  ;   }   int     main  ()     {      // Create a static hardcoded linked list:      // 1 -> 2 -> 3 -> 4 -> 5.      struct     Node  *     head     =     newNode  (  1  );      head  ->  next     =     newNode  (  2  );      head  ->  next  ->  next     =     newNode  (  3  );      head  ->  next  ->  next  ->  next     =     newNode  (  4  );      head  ->  next  ->  next  ->  next  ->  next     =     newNode  (  5  );      printf  (  'Original Linked List: '  );      printList  (  head  );      // Delete the middle node.      head     =     deleteMid  (  head  );      printf  (  'Linked List after deleting the middle node: '  );      printList  (  head  );      return     0  ;   }   
Java
   // Java program to delete middle of a linked list   class   Node     {      int     data  ;      Node     next  ;      Node  (  int     x  )     {      data     =     x  ;      next     =     null  ;      }   }   public     class   GfG     {      // Function to delete middle node from linked list.      public     static     Node     deleteMid  (  Node     head  )     {      // Edge case: return null if there is only      // one node.      if     (  head  .  next     ==     null  )      return     null  ;      int     count     =     0  ;      Node     p1     =     head       p2     =     head  ;      // First pass count the number of nodes      // in the linked list using 'p1'.      while     (  p1     !=     null  )     {      count  ++  ;      p1     =     p1  .  next  ;      }      // Get the index of the node to be deleted.      int     middleIndex     =     count     /     2  ;      // Second pass let 'p2' move toward predecessor      // of the middle node.      for     (  int     i     =     0  ;     i      <     middleIndex     -     1  ;     ++  i  )      p2     =     p2  .  next  ;      // Delete the middle node and return 'head'.      p2  .  next     =     p2  .  next  .  next  ;      return     head  ;      }      public     static     void     printList  (  Node     head  )     {      Node     temp     =     head  ;      while     (  temp     !=     null  )     {      System  .  out  .  print  (  temp  .  data     +     ' -> '  );      temp     =     temp  .  next  ;      }      System  .  out  .  println  (  'null'  );      }      public     static     void     main  (  String  []     args  )     {      // Create a static hardcoded linked list:      // 1 -> 2 -> 3 -> 4 -> 5.      Node     head     =     new     Node  (  1  );      head  .  next     =     new     Node  (  2  );      head  .  next  .  next     =     new     Node  (  3  );      head  .  next  .  next  .  next     =     new     Node  (  4  );      head  .  next  .  next  .  next  .  next     =     new     Node  (  5  );      System  .  out  .  print  (  'Original Linked List: '  );      printList  (  head  );      // Delete the middle node.      head     =     deleteMid  (  head  );      System  .  out  .  print      (  'Linked List after deleting the middle node: '  );      printList  (  head  );      }   }   
Python
   # Python3 program to delete middle of a linked list   class   Node  :   def   __init__  (  self     data  ):   self  .  data   =   data   self  .  next   =   None   # Function to delete middle node from linked list.   def   deleteMid  (  head  ):   # Edge case: return None if there is only   # one node.   if   head  .  next   is   None  :   return   None   count   =   0   p1   =   head   p2   =   head   # First pass count the number of nodes   # in the linked list using 'p1'.   while   p1   is   not   None  :   count   +=   1   p1   =   p1  .  next   # Get the index of the node to be deleted.   middleIndex   =   count   //   2   # Second pass let 'p2' move toward the predecessor   # of the middle node.   for   i   in   range  (  middleIndex   -   1  ):   p2   =   p2  .  next   # Delete the middle node and return 'head'.   p2  .  next   =   p2  .  next  .  next   return   head   def   printList  (  head  ):   temp   =   head   while   temp   is   not   None  :   print  (  temp  .  data     end  =  ' -> '  )   temp   =   temp  .  next   print  (  'None'  )   if   __name__   ==   '__main__'  :   # Create a static hardcoded linked list:   # 1 -> 2 -> 3 -> 4 -> 5.   head   =   Node  (  1  )   head  .  next   =   Node  (  2  )   head  .  next  .  next   =   Node  (  3  )   head  .  next  .  next  .  next   =   Node  (  4  )   head  .  next  .  next  .  next  .  next   =   Node  (  5  )   print  (  'Original Linked List:'     end  =  ' '  )   printList  (  head  )   # Delete the middle node.   head   =   deleteMid  (  head  )   print  (  'Linked List after deleting the middle node:'     end  =  ' '  )   printList  (  head  )   
C#
   // C# program to delete middle of a linked list   using     System  ;   class     Node     {      public     int     data  ;      public     Node     next  ;      public     Node  (  int     x  )     {      data     =     x  ;      next     =     null  ;      }   }   class     GfG     {      // Function to delete middle node from linked list.      static     Node     deleteMid  (  Node     head  )     {      // Edge case: return null if there is only      // one node.      if     (  head  .  next     ==     null  )      return     null  ;      int     count     =     0  ;      Node     p1     =     head       p2     =     head  ;      // First pass count the number of nodes      // in the linked list using 'p1'.      while     (  p1     !=     null  )     {      count  ++  ;      p1     =     p1  .  next  ;      }      // Get the index of the node to be deleted.      int     middleIndex     =     count     /     2  ;      // Second pass let 'p2' move toward the predecessor      // of the middle node.      for     (  int     i     =     0  ;     i      <     middleIndex     -     1  ;     ++  i  )      p2     =     p2  .  next  ;      // Delete the middle node and return 'head'.      p2  .  next     =     p2  .  next  .  next  ;      return     head  ;      }      static     void     printList  (  Node     head  )     {      Node     temp     =     head  ;      while     (  temp     !=     null  )     {      Console  .  Write  (  temp  .  data     +     ' -> '  );      temp     =     temp  .  next  ;      }      Console  .  WriteLine  (  'null'  );      }      static     void     Main  (  string  []     args  )     {      // Create a static hardcoded linked list:      // 1 -> 2 -> 3 -> 4 -> 5.      Node     head     =     new     Node  (  1  );      head  .  next     =     new     Node  (  2  );      head  .  next  .  next     =     new     Node  (  3  );      head  .  next  .  next  .  next     =     new     Node  (  4  );      head  .  next  .  next  .  next  .  next     =     new     Node  (  5  );      Console  .  Write  (  'Original Linked List: '  );      printList  (  head  );      // Delete the middle node.      head     =     deleteMid  (  head  );      Console  .  Write      (  'Linked List after deleting the middle node: '  );      printList  (  head  );      }   }   
JavaScript
   class     Node     {      constructor  (  data  )     {      this  .  data     =     data  ;      this  .  next     =     null  ;      }   }   // Function to delete middle node from linked list.   function     deleteMid  (  head  )     {      // Edge case: return null if there is only      // one node.      if     (  head  .  next     ===     null  )      return     null  ;      let     count     =     0  ;      let     p1     =     head       p2     =     head  ;      // First pass count the number of nodes      // in the linked list using 'p1'.      while     (  p1     !==     null  )     {      count  ++  ;      p1     =     p1  .  next  ;      }      // Get the index of the node to be deleted.      let     middleIndex     =     Math  .  floor  (  count     /     2  );      // Second pass let 'p2' move toward the predecessor      // of the middle node.      for     (  let     i     =     0  ;     i      <     middleIndex     -     1  ;     ++  i  )      p2     =     p2  .  next  ;      // Delete the middle node and return 'head'.      p2  .  next     =     p2  .  next  .  next  ;      return     head  ;   }   function     printList  (  head  )     {      let     temp     =     head  ;      while     (  temp     !==     null  )     {      console  .  log  (  temp  .  data     +     ' -> '  );      temp     =     temp  .  next  ;      }      console  .  log  (  'null'  );   }   // Create a static hardcoded linked list:   // 1 -> 2 -> 3 -> 4 -> 5.   let     head     =     new     Node  (  1  );   head  .  next     =     new     Node  (  2  );   head  .  next  .  next     =     new     Node  (  3  );   head  .  next  .  next  .  next     =     new     Node  (  4  );   head  .  next  .  next  .  next  .  next     =     new     Node  (  5  );   console  .  log  (  'Original Linked List: '  );   printList  (  head  );   // Delete the middle node.   head     =     deleteMid  (  head  );   console  .  log  (  'Linked List after deleting the middle node: '  );   printList  (  head  );   

الإخراج
Original Linked List: 1 -> 2 -> 3 -> 4 -> 5 -> nullptr Linked List after deleting the middle node: 1 -> 2 -> 4 -> 5 -> nullptr  

تعقيد الوقت: على). هناك حاجة إلى اجتيازين للقائمة المرتبطة
المساحة المساعدة: يا(1). ليس هناك حاجة إلى مساحة إضافية.

[النهج المتوقع] اجتياز مسار واحد بمؤشرات بطيئة وسريعة - وقت O(n) ومسافة O(1)

يتطلب الحل أعلاه اجتياز القائمة المرتبطة مرتين. يمكن حذف العقدة الوسطى باستخدام اجتياز واحد. والفكرة هي استخدام مؤشرين Slow_ptr و fast_ptr . يحرك المؤشر السريع عقدتين في كل مرة بينما يتحرك المؤشر البطيء عقدة واحدة في كل مرة. عندما يصل المؤشر السريع إلى نهاية القائمة، سيتم وضع المؤشر البطيء في العقدة الوسطى. بعد ذلك، تحتاج إلى توصيل العقدة التي تأتي قبل العقدة الوسطى ( السابق ) إلى العقدة التي تأتي بعد العقدة الوسطى. يؤدي هذا إلى تخطي العقدة الوسطى بشكل فعال وإزالتها من القائمة.

وفيما يلي تنفيذ النهج المذكور أعلاه

C++
   // C++ program to delete middle of a linked list   #include          using     namespace     std  ;   struct     Node     {      int     data  ;      Node  *     next  ;      Node  (  int     x  ){      data     =     x  ;      next     =     nullptr  ;      }   };   // Function to delete middle node from linked list   struct     Node  *     deleteMid  (  struct     Node  *     head  )     {      // If the list is empty return NULL      if     (  head     ==     NULL  )      return     NULL  ;      // If the list has only one node      // delete it and return NULL      if     (  head  ->  next     ==     NULL  )     {      delete     head  ;      return     NULL  ;      }      struct     Node  *     prev     =     NULL  ;      struct     Node  *     slow_ptr     =     head  ;      struct     Node  *     fast_ptr     =     head  ;      // Move the fast pointer 2 nodes ahead      // and the slow pointer 1 node ahead      // until fast pointer reaches end of the list      while     (  fast_ptr     !=     NULL     &&     fast_ptr  ->  next     !=     NULL  )     {      fast_ptr     =     fast_ptr  ->  next  ->  next  ;         // Update prev to hold the previous       // slow pointer value      prev     =     slow_ptr  ;         slow_ptr     =     slow_ptr  ->  next  ;         }      // At this point slow_ptr points to middle node      // Bypass the middle node      prev  ->  next     =     slow_ptr  ->  next  ;      // Delete the middle node      delete     slow_ptr  ;         // Return the head of the modified list      return     head  ;   }   void     printList  (  struct     Node  *     head  )     {      struct     Node  *     temp     =     head  ;      while     (  temp     !=     NULL  )     {      cout      < <     temp  ->  data      < <     ' -> '  ;      temp     =     temp  ->  next  ;      }      cout      < <     'NULL'      < <     endl  ;   }   int     main  ()     {      // Create a static hardcoded linked list:      // 1 -> 2 -> 3 -> 4 -> 5      Node  *     head     =     new     Node  (  1  );      head  ->  next     =     new     Node  (  2  );      head  ->  next  ->  next     =     new     Node  (  3  );      head  ->  next  ->  next  ->  next     =     new     Node  (  4  );      head  ->  next  ->  next  ->  next  ->  next     =     new     Node  (  5  );      cout      < <     'Original Linked List: '  ;      printList  (  head  );      // Delete the middle node      head     =     deleteMid  (  head  );      cout      < <     'Linked List after deleting the middle node: '  ;      printList  (  head  );      return     0  ;   }   
C
   // C program to delete middle of a linked list   #include         #include         struct     Node     {      int     data  ;      struct     Node  *     next  ;   };   // Function to delete middle node from linked list   struct     Node  *     deleteMid  (  struct     Node  *     head  )     {      // If the list is empty return NULL      if     (  head     ==     NULL  )      return     NULL  ;      // If the list has only one node      // delete it and return NULL      if     (  head  ->  next     ==     NULL  )     {      free  (  head  );      return     NULL  ;      }      struct     Node  *     prev     =     NULL  ;      struct     Node  *     slow_ptr     =     head  ;      struct     Node  *     fast_ptr     =     head  ;      // Move the fast pointer 2 nodes ahead      // and the slow pointer 1 node ahead      // until fast pointer reaches end of the list      while     (  fast_ptr     !=     NULL     &&     fast_ptr  ->  next     !=     NULL  )     {      fast_ptr     =     fast_ptr  ->  next  ->  next  ;      // Update prev to hold the previous       // slow pointer value      prev     =     slow_ptr  ;      slow_ptr     =     slow_ptr  ->  next  ;      }      // At this point slow_ptr points to middle node      // Bypass the middle node      prev  ->  next     =     slow_ptr  ->  next  ;      // Delete the middle node      free  (  slow_ptr  );      // Return the head of the modified list      return     head  ;   }   void     printList  (  struct     Node  *     head  )     {      struct     Node  *     temp     =     head  ;      while     (  temp     !=     NULL  )     {      printf  (  '%d -> '       temp  ->  data  );      temp     =     temp  ->  next  ;      }      printf  (  'NULL  n  '  );   }   struct     Node  *     newNode  (  int     x  )     {      struct     Node  *     temp     =         (  struct     Node  *  )  malloc  (  sizeof  (  struct     Node  ));      temp  ->  data     =     x  ;      temp  ->  next     =     NULL  ;      return     temp  ;   }   int     main  ()     {      // Create a static hardcoded linked list:      // 1 -> 2 -> 3 -> 4 -> 5.      struct     Node  *     head     =     newNode  (  1  );      head  ->  next     =     newNode  (  2  );      head  ->  next  ->  next     =     newNode  (  3  );      head  ->  next  ->  next  ->  next     =     newNode  (  4  );      head  ->  next  ->  next  ->  next  ->  next     =     newNode  (  5  );      printf  (  'Original Linked List: '  );      printList  (  head  );      // Delete the middle node.      head     =     deleteMid  (  head  );      printf  (  'Linked List after deleting the middle node: '  );      printList  (  head  );      return     0  ;   }   
Java
   // Java program to delete the middle of a linked list   class   Node     {      int     data  ;      Node     next  ;      Node  (  int     x  )     {      data     =     x  ;      next     =     null  ;      }   }   class   GfG     {      // Function to delete middle node from linked list      static     Node     deleteMid  (  Node     head  )     {      // If the list is empty return null      if     (  head     ==     null  )      return     null  ;      // If the list has only one node      // delete it and return null      if     (  head  .  next     ==     null  )     {      return     null  ;      }      Node     prev     =     null  ;      Node     slow_ptr     =     head  ;      Node     fast_ptr     =     head  ;      // Move the fast pointer 2 nodes ahead      // and the slow pointer 1 node ahead      // until fast pointer reaches end of list      while     (  fast_ptr     !=     null         &&     fast_ptr  .  next     !=     null  )     {      fast_ptr     =     fast_ptr  .  next  .  next  ;      // Update prev to hold the previous       // slow pointer value      prev     =     slow_ptr  ;      slow_ptr     =     slow_ptr  .  next  ;      }      // At this pointslow_ptr points to middle node      // Bypass the middle node      prev  .  next     =     slow_ptr  .  next  ;      // Return the head of the modified list      return     head  ;      }          static     void     printList  (  Node     head  )     {      Node     temp     =     head  ;      while     (  temp     !=     null  )     {      System  .  out  .  print  (  temp  .  data     +     ' -> '  );      temp     =     temp  .  next  ;      }      System  .  out  .  println  (  'NULL'  );      }          public     static     void     main  (  String  []     args  )     {      // Create a static hardcoded linked list:      // 1 -> 2 -> 3 -> 4 -> 5      Node     head     =     new     Node  (  1  );      head  .  next     =     new     Node  (  2  );      head  .  next  .  next     =     new     Node  (  3  );      head  .  next  .  next  .  next     =     new     Node  (  4  );      head  .  next  .  next  .  next  .  next     =     new     Node  (  5  );      System  .  out  .  print  (  'Original Linked List: '  );      printList  (  head  );      // Delete the middle node      head     =     deleteMid  (  head  );      System  .  out  .  print      (  'Linked List after deleting the middle node: '  );      printList  (  head  );      }   }   
Python
   # Python program to delete the middle of a linked list   class   Node  :   def   __init__  (  self     data  ):   self  .  data   =   data   self  .  next   =   None   # Function to delete middle node from linked list   def   deleteMid  (  head  ):   # If the list is empty return None   if   head   is   None  :   return   None   # If the list has only one node   # delete it and return None   if   head  .  next   is   None  :   return   None   prev   =   None   slow_ptr   =   head   fast_ptr   =   head   # Move the fast pointer 2 nodes ahead   # and the slow pointer 1 node ahead   # until fast pointer reaches end of the list   while   fast_ptr   is   not   None   and   fast_ptr  .  next   is   not   None  :   fast_ptr   =   fast_ptr  .  next  .  next   # Update prev to hold the previous   # slow pointer value   prev   =   slow_ptr   slow_ptr   =   slow_ptr  .  next   # At this point slow_ptr points to middle node   # Bypass the middle node   prev  .  next   =   slow_ptr  .  next   # Return the head of the modified list   return   head   def   printList  (  head  ):   temp   =   head   while   temp  :   print  (  temp  .  data     end  =  ' -> '  )   temp   =   temp  .  next   print  (  'NULL'  )   if   __name__   ==   '__main__'  :   # Create a static hardcoded linked list:   # 1 -> 2 -> 3 -> 4 -> 5   head   =   Node  (  1  )   head  .  next   =   Node  (  2  )   head  .  next  .  next   =   Node  (  3  )   head  .  next  .  next  .  next   =   Node  (  4  )   head  .  next  .  next  .  next  .  next   =   Node  (  5  )   print  (  'Original Linked List: '     end  =  ''  )   printList  (  head  )   # Delete the middle node   head   =   deleteMid  (  head  )   print  (  'Linked List after deleting the middle node: '     end  =  ''  )   printList  (  head  )   
C#
   // C# program to delete middle of a linked list   using     System  ;   class     Node     {      public     int     data  ;      public     Node     next  ;          public     Node  (  int     x  )     {      data     =     x  ;      next     =     null  ;      }   }   class     GfG     {      // Function to delete middle node from linked list      public     static     Node     deleteMid  (  Node     head  )     {      // If the list is empty return null      if     (  head     ==     null  )      return     null  ;      // If the list has only one node      // delete it and return null      if     (  head  .  next     ==     null  )     {      return     null  ;      }      Node     prev     =     null  ;      Node     slow_ptr     =     head  ;      Node     fast_ptr     =     head  ;      // Move the fast pointer 2 nodes ahead      // and the slow pointer 1 node ahead      // until fast pointer reaches end of the list      while     (  fast_ptr     !=     null     &&     fast_ptr  .  next     !=     null  )     {      fast_ptr     =     fast_ptr  .  next  .  next  ;      // Update prev to hold the previous       // slow pointer value      prev     =     slow_ptr  ;      slow_ptr     =     slow_ptr  .  next  ;      }      // At this point slow_ptr points to middle node      // Bypass the middle node      prev  .  next     =     slow_ptr  .  next  ;      // Return the head of the modified list      return     head  ;      }      // Function to print the linked list      public     static     void     printList  (  Node     head  )     {      Node     temp     =     head  ;      while     (  temp     !=     null  )     {      Console  .  Write  (  temp  .  data     +     ' -> '  );      temp     =     temp  .  next  ;      }      Console  .  WriteLine  (  'NULL'  );      }      public     static     void     Main  (  string  []     args  )     {      // Create a static hardcoded linked list:      // 1 -> 2 -> 3 -> 4 -> 5      Node     head     =     new     Node  (  1  );      head  .  next     =     new     Node  (  2  );      head  .  next  .  next     =     new     Node  (  3  );      head  .  next  .  next  .  next     =     new     Node  (  4  );      head  .  next  .  next  .  next  .  next     =     new     Node  (  5  );      Console  .  Write  (  'Original Linked List: '  );      printList  (  head  );      // Delete the middle node      head     =     deleteMid  (  head  );      Console  .  Write      (  'Linked List after deleting the middle node: '  );      printList  (  head  );      }   }   
JavaScript
   // javascript program to delete middle of a linked list   class     Node     {      constructor  (  data  )      {      this  .  data     =     data  ;      this  .  next     =     null  ;      }   }   // Function to delete the middle node from the linked list   function     deleteMid  (  head  )   {      // If the list is empty return null      if     (  head     ===     null  )     {      return     null  ;      }      // If the list has only one node delete it and return      // null      if     (  head  .  next     ===     null  )     {      return     null  ;      }      let     prev     =     null  ;      let     slow_ptr     =     head  ;      let     fast_ptr     =     head  ;      // Move the fast pointer 2 nodes ahead      // and the slow pointer 1 node ahead      // until the fast pointer reaches the end of the list      while     (  fast_ptr     !==     null     &&     fast_ptr  .  next     !==     null  )     {      fast_ptr     =     fast_ptr  .  next  .  next  ;      // Update prev to hold the previous slow pointer      // value      prev     =     slow_ptr  ;      slow_ptr     =     slow_ptr  .  next  ;      }      // At this point slow_ptr points to the middle node      // Bypass the middle node      prev  .  next     =     slow_ptr  .  next  ;      // Return the head of the modified list      return     head  ;   }   function     printList  (  head  )   {      let     temp     =     head  ;      while     (  temp     !==     null  )     {      process  .  stdout  .  write  (  temp  .  data     +     ' -> '  );      temp     =     temp  .  next  ;      }      console  .  log  (  'null'  );   }   // Create a static hardcoded linked list:   // 1 -> 2 -> 3 -> 4 -> 5   let     head     =     new     Node  (  1  );   head  .  next     =     new     Node  (  2  );   head  .  next  .  next     =     new     Node  (  3  );   head  .  next  .  next  .  next     =     new     Node  (  4  );   head  .  next  .  next  .  next  .  next     =     new     Node  (  5  );   process  .  stdout  .  write  (  'Original Linked List: '  );   printList  (  head  );   // Delete the middle node   head     =     deleteMid  (  head  );   process  .  stdout  .  write  (      'Linked List after deleting the middle node: '  );   printList  (  head  );   

الإخراج
Original Linked List: 1 -> 2 -> 3 -> 4 -> 5 -> NULL Linked List after deleting the middle node: 1 -> 2 -> 4 -> 5 -> NULL  

تعقيد الوقت: على). هناك حاجة إلى اجتياز واحد فقط للقائمة المرتبطة
المساحة المساعدة: يا(1). حيث لا توجد حاجة إلى مساحة إضافية.

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